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OlgaM077 [116]
4 years ago
5

Which expression will give a close estimate for 10,033 ÷ 1,171?

Mathematics
2 answers:
zloy xaker [14]4 years ago
8 0
We can round each to the nearest thousand:
 
10,033 to 10,000 and 1,171 to 1,000.

Giving us:

<span>10,000 ÷ 1,000</span>
qaws [65]4 years ago
7 0

Answer:

B) 10,00 / 1,000

Step-by-step explanation:

Just round both of the numbers to the nearest thousand.

10,033 rounded is 10,000

1,171 rounded is 1,000 and there's your answer

When estimating if its over 5, 50, 500, ect then you round up.

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Ksju [112]
Pemdas

in the parenthasees, we have 2*3 which is 6
then 6+21=27
now we have
(1/3)(27) times 3^2-5.6
exponents,, 3^2=9

(1/3)(27)(9)-5.6
multiply
81-5.6
minus
75.4
5 0
4 years ago
A group of people are going on a 5 mil hike. They walked 2 1/10 miles in the morning and 1 1/4 mils during the first hr of the a
Ugo [173]
Answer: 1 13/20 miles

Explanation:

5 -  2\cfrac{1}{10} - 1 \cfrac{1}{4} = 5 \cfrac{0}{20}  -  2\cfrac{2}{20} - 1 \cfrac{5}{20} =   4 \cfrac{20}{20}  -  2\cfrac{2}{20} - 1 \cfrac{5}{20} =  1 \cfrac{13}{20}
8 0
3 years ago
A complex number is a number of the form a+bi, where:
likoan [24]
The answer is C.

a is a real number in this case, and bi is an imaginary number because i is an imaginary number. 
8 0
3 years ago
Read 2 more answers
It takes Elsa 10 minutes to mix up a batch of muffins the muffins bake for 20 minutes and then cool for one hour then Elsa spend
Levart [38]
It takes her 105 minutes in total
5 0
3 years ago
Determine what type of model best fits the given situation: An Internet phone company presently provides service to 5,000 custom
bagirrra123 [75]

Answer:

The best fit is <em>A. Linear model</em>

<em></em>

Step-by-step explanation:

Given:

Monthly Rate = $20, Number of customers = 5000

If there is a decrease of $1 in the monthly rate, the number of customers increase by 500.

To find:

The type of model that best fits the given situation?

Solution:

Monthly Rate = $20, Number of customers = 5000

Let us decrease the monthly rate by $1.

Monthly Rate = $20 - $1  = $19, Number of customers = 5000 + 500 = 5500

Let us decrease the monthly rate by $1 more.

Monthly Rate = $19 - $1  = $18, Number of customers = 5500 + 500 = 6000

Here, we can see that there is a <em>linear change </em> in the number of customers whenever there is decrease in the monthly rate.

We have 2 pair of values here,

x = 20, y = 5000

x = 19, y = 5500

Let us write the equation in slope intercept form:

y =mx+c

Slope of a function:

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{5500-5000}{19-20}\\\Rightarrow -500

So, the equation is:

y =-500x+c

Putting x = 20, y = 5000:

5000 =-500\times 20+c\\\Rightarrow c = 5000 +10000 = 15000

\Rightarrow \bold{y =-500x+15000}

Let us check whether (18, 6000) satisfies it.

Putting x = 18:

-500 \times 18 +15000 = -9000+15000 = 6000 so, it is true.

So, the answer is:

The best fit is <em>A. Linear model</em>

6 0
4 years ago
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