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Goshia [24]
3 years ago
6

Which transformation(s) can map TriangleMNQ onto TrianglePQN?

Mathematics
2 answers:
polet [3.4K]3 years ago
6 0
The answer is Translation only
Aleks [24]3 years ago
3 0

Answer:

Translation

Step-by-step explanation:

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Rachel Newton scored 26 points in a recent basketball game without making any 3-point shots. She scored 19 times, making several
Readme [11.4K]

Answer:

She made 7  field goals

Step-by-step explanation:

With the data we can make 2 equations

1 x + 2 y= 26

x+y=19  and y=19-x

Where,

x= free throws

y=field goals

Replacing y in the first equation

1 x + 2 (19-x)= 26

1 x + 38-2x= 26

1 x - 2x= 26 - 38

- 1x= -12

x=12

y=19-12

y=7

7 0
3 years ago
Which of the following is not true about histograms?
Brut [27]
The letter a d e is false the right one is c
3 0
4 years ago
Read 2 more answers
in this situation negative $55 represents a debit of blank on Thursday mom had a debit of blank than $55
LiRa [457]
She had $110 more than -55 hope this helps
5 0
3 years ago
(a) Complete the table of values for y = 6 - 4x.<br><br> Please help ❤️
shutvik [7]

<u>Answer:</u>

\boxed{\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}}

<u>Step-by-step explanation:</u>

Given equation to us is :-

\implies y = 6 - 4x

So , here we can put different values of x in order to get different values of y .

Initial table given to us is ,

\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & & & 2&&-6 \\\cline{1-6}\end{tabular}

<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>:</u><u>-</u>

\implies y = 6 - 4x \\\\\implies y = 6 -4(-1) \\\\\implies y = 6 + 4 \\\\\red{\bf\implies y = 10}

<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

\implies y = 6 - 4x \\\\\implies y = 6-4(0) \\\\\implies y = 6 - 0 \\\\\pink{\bf\implies y = 6 }

<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u>

\implies y = 6-4x \\\\\implies y = 6 - 4(2) \\\\\implies y = 6 - 8 \\\\\blue{\bf\implies y = (-2)}

<u>Hence </u><u>the</u><u> </u><u>final</u><u> </u><u>table</u><u> </u><u>would</u><u> </u><u>be</u><u> </u><u>:</u><u>-</u><u> </u>

\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}

4 0
3 years ago
Help ....,?.?.??.?.?..?.?.?.?
SVETLANKA909090 [29]

Answer:

1

Step-by-step explanation:

4 0
3 years ago
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