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natima [27]
3 years ago
8

Find the fifth term of (2x + y)10.

Mathematics
1 answer:
kkurt [141]3 years ago
5 0
Im guessing the first answer
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Find the LCD of the fractions, and then simplify the expression. Assume that no denominator equals zero. 5/(3x^2y) - 4/(6xy^3
tamaranim1 [39]
The LCD = 6x^2y^3    ( because LCD of 3 and 6 = 6,  LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)

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5(2y^2) - 4(x)
------------------
   6x^2y^3

=  2( 5y^2 - 2x)
   -----------------
        6x^2y^3

=    5y^2 - 2x
      -----------
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3 years ago
Eighth grade Y.14 Solve equations with the distributive property SRP Solve for u. -9.6u - 6.96 = -3(2.4u – 4.72) – = U = Submit​
Vladimir79 [104]

Answer:

2.93 repeating

Step-by-step explanation:

4 0
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