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iogann1982 [59]
3 years ago
6

-2x2 - x + 7 +x2 +4x-5

Mathematics
1 answer:
Arada [10]3 years ago
6 0

Answer:

Need more?

Step-by-step explanation:

-x^2 + 3x + 2

Is this the answer?

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What is tan(x)-5=0<br> (With steps)
gizmo_the_mogwai [7]
\tan x-5=0
\tan x=5

Now before taking the inverse tangent of both sides, recall that

\tan x=\tan(x\pm\pi)=\tan(x\pm2\pi)=\cdots=\tan(x\pm n\pi)

where n is any integer. This means that when taking the inverse tangent of \tan x, instead of just x, we would end up with

\arctan(\tan x)=\arctan(\tan(x+n\pi))=x\pm n\pi

So after doing so in the equation above, we're left with

x\pm n\pi=\arctan5\implies x=\arctan5\pm n\pi

As n can be any integer, including negative integers, we can simply write

x=\arctan5+n\pi,\,n\in\mathbb Z
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