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Juli2301 [7.4K]
3 years ago
8

The sum of the first 12 terms of a geometric sequence with 10 as the first term and a common ratio of 0.3 is __________.

Mathematics
1 answer:
BaLLatris [955]3 years ago
7 0

Answer: 14.2638366937

Step-by-step explanation:

A geometric sequence is a sequence in which each term is multiplied by a number, called the common ratio, to get the next term.

So, if the first term of the geometric sequence is 10 and the common ratio is 0.3, the sequence would be 10, 0.3(10), 0.3 x 0.3 x 10... and so forth. This becomes:

10, 3, 0.9, 0.27, 0.081, 0.00243, 0.00729, 0.002187, 0.0006561, 0.00019683, 0.000059049, 0.0000177147...

You add these first 12 terms to get 14.2638366937.

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Answer:

3/11

Step-by-step explanation:

From the above question, we have the following information

Total number of balls = 12

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C(n, r) = nCr = n!/r!(n - r)!

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The chance/probability of drawing out 3 balls = 12C3 = 12!/3! × (12 - 3)! = 12!/3! × 9!

= 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1/(3 × 2 × 1) × (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

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To find the chance that all the three balls are selected,

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