9514 1404 393
Answer:
9.5°, yes
Step-by-step explanation:
The relevant trig relation is ...
Tan = Opposite/Adjacent
The distance opposite the angle of elevation is the plane's height, 500 m. The distance adjacent to the angle of elevation is the horizontal distance to the plane, 3 km = 3000 m. Then the angle is found from ...
tan(α) = 500/3000 = 1/6
α = arctan(1/6) ≈ 9.46°
The plane is approaching at an angle of 9.46°. It is safe to land, since that angle is less than 15°.
_____
<em>Additional comment</em>
The usual descent angle for most commercial air traffic is 3°. Some airport geography demands it be different (steeper). A higher descent angle can put undue stress on the landing gear.
Answer:
a certain number that i do not know
Step-by-step explanation:
Answer: The correct answer would be -85.
Step-by-step explanation: This is because the -5 becomes positive because it is inside parentheses.
This would make the expression: -425 ÷ 5.
-425 ÷ 5 is equal to -85.
Hope this helps and have a nice day! :)
Answer:
5 is the leading coefficient
