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2 years ago

The graph of the equation below is a circle. What is the length of the radius of the circle? (x - 4)2 + (y + 12)2 = 172

1 answer:

defon2 years ago

3 0

Hello :
an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =4 and b = -12
 the length of the radius is : r = √172

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Choose a value for b so that the relation below is not a function.

Elena-2011 [213]

Answer:

B. -2

Step-by-step explanation:

A relation that is not a function would have one x-value having two different corresponding y-values.

If we choose -2 to represent b I the relation, the relation would not be a function. This is because, we there would be two different y-values, 8 and 1, that are assigned to one x-value, which is -2 ==> (-2, 8) and (-2, 1).

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2 years ago

OTHER ONE WASNT 50. 50 POINTS AND BRAINLIST IF GET RIGHT

nexus9112 [7]

Answer:

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Step-by-step explanation:

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2 years ago

Solve the exponential equation help, it's for homework

swat32

Answer: x = 3

Step-by-step explanation:

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3-2x = -x

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2 years ago

Wayne bought blueberries. He uses 3/8 of the blueberries to make blueberry bread, 1/6 of the blueberries to make pancakes, and 5

yKpoI14uk [10]

Answer:

Wayne bought 72 blueberries.

Step-by-step explanation:

To combine the fractions, convert all of the fractions to a denominator of 24.

3/8 * 3/3 = 9/24

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5/12 * 2/2 = 10/24

Now add together the fractions

9/24 + 4/24 + 10/24 = 23/24

He used 23/24 of his blueberries, or 69 of them.

To find the total amount of blueberries, divide 69 by 23, then multiply that number b 24.

69 / 23 = 3

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Wayne bought 72 blueberries.

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3 years ago

Read 2 more answers

Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently

garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

$\small \sum_{i = 1}^{k} L_i= 2\pi$

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

$\small \sum_{i = 1}^{k} C_i.l = 2\pi$

where C(i) is a constant coefficient obviously between 0 and 1.

$\small \sum_{i = 1}^{k} C_i= 2\pi/l$

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

$\small L_{Exp} = \frac{2\pi}{k}$

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2 years ago