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Oduvanchick [21]
3 years ago
11

PLEASE HELP ITS URGENT DONT GUESS (also if you get it right ill mark you as brainliest)

Mathematics
2 answers:
Artemon [7]3 years ago
5 0

Answer:

Circumference is 25.1=

8\pi

Area is 50.2=

16\pi

My name is Ann [436]3 years ago
4 0

Answer:

25.12 is the Circumference Area is 50.24

Step-by-step explanation:

Area is cm2 Circumference is cm

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Find the length of UV.
katovenus [111]
7x-8 (2) = 12x+8
14x-16 = 12x+8
-12x -12x
2x-16 = 8
+16 +16
2x = 24

÷2 ÷2
x= 12

UV= 7x-8
UV= 7(12)-8
UV= 84-8
UV= 76
7 0
2 years ago
41 lb =<br>oz<br>B 656<br>C 2<br>D 820​
11111nata11111 [884]

Answer:

B 656oz

Step-by-step explanation:

8 0
3 years ago
Michael's dad is 30 years of age. He is 2 years more than four times Michaels age m. Write and solve a two-step equation to dete
Ksenya-84 [330]

Answer:

The two step equation that we can use to find michael's age is x = (f-2)/4 where f = 30. So Michael is 7 years old.

Step-by-step explanation:

In order to solve this problem we will attribute variables to the ages of Michael and his father. For his father age we will attribute a variable called "f" and for Michael's age we will attribute a variable called "x". The first information that the problem gives us is that Michael's dad is 30 years of age, so we have:

f = 30

Then the problem states that the age of the father is 2 years "more" than four "times" Michaels age. The "more" implies a sum and the "times" implies a product, so we have:

f = 2 + 4*x

We can now find Michael's age, for that we need to isolate the "x" variable. We have:

f - 2 = 4*x

4*x = f - 2

x = (f-2)/4

x = (30 - 2)/4 = 7 years

The two step equation that we can use to find michael's age is x = (f-2)/4 where f = 30. So Michael is 7 years old.

7 0
3 years ago
Read 2 more answers
A search committee is formed to find a new software engineer. (a) If 100 applicants apply for the job, how many ways are there t
vagabundo [1.1K]

These are three questions with three complete answers.

Answers:

(a) C(100,6) = 100! / [ 9! × (100 -9)! ] =

              = (100×99×98×97×96×95×94×93×92) / (9×8×7×6×5×4×3×2×1) =

              = 1,902,231,808,400

(b) C(9,6) = 9! / [ 6! * (9 - 6)! ] = 9! / [6! 3!] = (9 × 8 × 7 × 6!) (6! × 3 × 2 × 1) =

          =  (9 × 8 × 7 × 6!) (6! × 3 × 2 × 1) =  (9 × 8 × 7 ) / (3 × 2 × 1) = 84

(c) P(6,3) = 6! / (6 - 3)! = 6! / 3! = (6 × 5 × 4 × 3!) / 3! = 120

Step-by-step explanation:

(a) If 100 applicants apply for the job, how many ways are there to select a subset of 9 for a short list?

This is the formula for combinations: C (m,n) = m! / [n! (m - n)! ].

We will also use the formula for permutations, only as an intermediate step, to explain the solution. The formula for permutations is: P (m,n) = m! / (m - n)!

Next you will see why the final formula that you can use to solve the problem is that of combinations (because the order in which you make the list does not matter) and how you use it.

You have to select a subset of 9 candidates from a list of 100 applicants.

The first candidate may be chosen from the 100 different applicants, the second candidate may be chosen from the 99 left applicants, the third candidate from 98 applicants, and so on, which leads to:

  • 100 × 99 × 98 × 97 × 96 × 95 × 94 × 93 × 92 possible variants.

Note that this is the permutation of 100 candidates taken from 9 in 9:

P(100,9)  = 100! (100 - 9)! = 100! / (91!) =

              = 100 × 99 × 98 × 97 × 96 × 95 × 94 × 93 × 92 × 91! / 91! =

              = 100× 99 × 98 × 97 × 96 × 95 × 94 × 93 × 92.

But you have to eliminate the repetitions!

Suppose that A, B, C, D, E, F, G, H, I represents the set formed by nine selected members whose names are A, B, C, D, E, F, G, H and I. So, any combination of those same names, written in different order, represents the same set (list). That means that there are 9! = 9× 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 equivalent lists.

That is why you must divide the first result (possible ways in which you can select nine candidates) by the number of ways that represent the same list for every set.

So, the conclusion is that the number of different lists of nine candidates is:

C(100,6) = 100! / [ 9! × (100 -9)! ] =

              = (100×99×98×97×96×95×94×93×92) / (9×8×7×6×5×4×3×2×1) =

              = 1,902,231,808,400

(b) If 6 of the 9 are selected for an interview, how many ways are there to pick the set of people who are interviewed? (You can assume that the short list is already decided).

Since, the short list, i.e. the  subset of 9 candidates is already decided, you will select 6 candidates to interview from 9 possible candidates.

So, your final set of candidates to interview will be the combination of 9 candidates taken from 6 in 6. The order of the names A, B, C, D, E, F, and G, is not relevant, and, therefore, the formula to use is that of combinations:

  • C (m,n) = m! / [n! (m - n)! ]

  • C(9,6) = 9! / [ 6! * (9 - 6)! ] = 9! / [6! 3!] = (9 × 8 × 7 × 6!) (6! × 3 × 2 × 1) =

                   =  (9 × 8 × 7 × 6!) (6! × 3 × 2 × 1) =  (9 × 8 × 7 ) / (3 × 2 × 1) = 84

(c) Based on the interview, the committee will rank the top three candidates and submit the list to their boss who will make the final decision. (You can assume that the interviewees are already decided.) How many ways are there to select the list from the 6 interviewees?

Ranking the top three candidates means that the order matters. Because it is not the same A, B, C than A, C, B, nor B, A, C, nor B, C, A, nor C, A, B, nor C, A, B.

Hence, you have to use the formula for permutations (not combinations).

The formula is: P(m,n) = m! / (m - n)!

Here, you must rank (select) 3 names, from a set (list) of 6 names, and the formula yields to:

  • P(6,3) = 6! / (6 - 3)! = 6! / 3! = (6 × 5 × 4 × 3!) / 3! = 120

4 0
3 years ago
Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of $ 65 $65dollar sign, 65 along with an h
user100 [1]

Answer:

Step-by-step explanation:

Basic Charge = $ 65

Rate per hour = $ 28

Number of hours = H

Rate for H hours = 28 *H = 28H

Equation:

65 + 28H ≤ 250

7 0
3 years ago
Read 2 more answers
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