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Oduvanchick [21]
3 years ago
11

PLEASE HELP ITS URGENT DONT GUESS (also if you get it right ill mark you as brainliest)

Mathematics
2 answers:
Artemon [7]3 years ago
5 0

Answer:

Circumference is 25.1=

8\pi

Area is 50.2=

16\pi

My name is Ann [436]3 years ago
4 0

Answer:

25.12 is the Circumference Area is 50.24

Step-by-step explanation:

Area is cm2 Circumference is cm

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a high school athlete Department bought 40 soccer uniforms at a cost of $3,000. After soccer season, they returned some of the u
GarryVolchara [31]

(3,000 / 40) - 40x =

7 0
3 years ago
-4.35
Advocard [28]

Answer:

The answer is -4.35

Step-by-step explanation:

3/8 = 0.375

x = 0.4

Now,

3/8x - 4.5

0.375 × 0.4 - 4.5

0.15 - 4.5 = -4.35

Thus, The answer is -4.35

<u>-TheUnknownScientist</u><u> 72</u>

7 0
3 years ago
The question is in the picture.
dangina [55]
<h2><u>Part A:</u></h2>

Let's denote no of seats in first row with r1 , second row with r2.....and so on.

r1=5

Since next row will have 10 additional row each time when we move to next row,

So,

r2=5+10=15

r3=15+10=25

<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>

r1=5=5+0=5+0×10=5+(1-1)×10

r2=15=5+10=5+(2-1)×10

r3=25=5+20=5+(3-1)×10

<u>So for nth row,</u>

rn=5+(n-1)×10

Since 5=r1 and 10=common difference (d)

rn=r1+(n-1)d

Since 'a' is a convention term for 1st term,

<h3><u>⇒</u><u>rn=a+(n-1)d</u></h3>

which is an explicit formula to find no of seats in any given row.

<h2><u>Part B:</u></h2>

Using above explicit formula, we can calculate no of seats in 7th row,

r7=5+(7-1)×10

r7=5+(7-1)×10 =5+6×10

r7=5+(7-1)×10 =5+6×10 =65

which is the no of seats in 7th row.

8 0
3 years ago
State which theorem you can use to show that the quadrilateral is a parallelogram.​
tekilochka [14]

Answer:

If one pair of opposite sides in a four sided figure are both opposite and parallel, then the figure is a parallelogram.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
B. Determine the values of a and b so that f is continuous.<br><br> Please help!
wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to  4a-2b+3 = 4\\\\  \therefore \ \ 4a-2b = 1\\\\

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\  

So,

\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3

\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\

In equation a multiply the by -2 and then add in the equation b:

\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to   a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to   -2b = -1\\\\ \to b = \frac{1}{2}  

So, the value of a \ and \ b= \frac{1}{2}

4 0
3 years ago
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