Given:
Oil flow: n(t) = 7t where t is time and n = how far the oil is spreading
Area of the circular pattern the oil is forming:
A(n) = πn²
<span>Part A: Find the area of the circle of spilled oil as a function of time, or A[n(t)]
A[n(t)] = </span>π (7t)² = π * 49 * t²
<span>How large is the area of spilled oil after 8 minutes?
n(t) = 7t </span>→ 7 * 8 = 56
A(56) = 3.14 * 56² = 9,847.04 square units
or
A[n(t)] = π (7t)²
A[n(8)] = 3.14 * (7*8)² = 3.14 * 3,136 = 9,847.04 square units
Answer:
y =
x - 4
Step-by-step explanation:
Given
4x - 3y = 12 ( subtract 4x from both sides )
- 3y = - 4x + 12 ( divide terms by - 3 )
y =
- 4 ← in the form y = mx + b
From 1-60, 4 and 6 a few common multiples. Find those multiples, which are
12, 24, 36, 48, 60.
So in 60 seconds, they blink together 5 times.
*see attached picture for the diagram of the box
Answer:
130cm²
Step-by-step explanation
The amount of red appear needed by Marcus to cover his box = Surface Area of the cube - Area of the circle.
Surface area of cube = 6s² (where s is the side length of the cube. s² therefore is S.A of 1 face of the cube)
Given that s = 5cm,
S.A of cube = 6s² = 6*5² = 150cm²
Area of circle = πr²;
Given that π = 3.14, and r = ½ of diameter of circle (i.e. ½ of side length of cube)
Area of circle = 3.14*(½*5)² = 3.14*(2.5)² = 3.14*6.25 =19.625
Amount of red paper needed = S.A of the cube - Area of the circle = 150cm² - 19.625cm² = 130.375cm² = 130cm²