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3 years ago

A boat moves initially at 10 m/s, then accelerates at 2 m/s^2 for 10 s. What is the velocity of the boat after 10 s?

Physics

1 answer:

Fudgin [204]3 years ago

6 0

Answer:

30 m/s

Explanation:

A boat moves initially at 10 m/s

The boat accelerates at 2 m/s^2 for 10 seconds

We are required to calculate the final velocity (v)

Therefore the velocity of the boat can be calculated as follows

v = u + at

u= 10 m/s

a= 2 m/s^2

t= 10 seconds

v= 10 + 2(10)

v= 10 + 20

= 30 m/s

Hence the velocity of the boat after 10 seconds is 30 m/s

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A ski gondola is connected to the top of a hill by a steel cable oflength 620 m and diameter 1.5 cm. As thegondola comes to the

klemol [59]

Answer:

Explanation:

Given

Length of cable $L=620 m$

Diameter of cable $d=1.5 cm$

time taken to return to original position $T=14 s$

time taken to cover distance L

$t=\frac{T}{2}=7 s$

velocity

$v=\frac{L}{t}=\frac{620}{7}=88.57 m/s$

(b)Relation between velocity of wave Tension is

$v=\sqrt{\frac{T}{\mu }} , where \mu =$ mass per unit Length

$T=v^2\cdot \mu$

$T=(88.57)^2\cdot \frac{m}{L}$

$T=(88.57)^2\cdot \frac{\rho AL}{L}$

where $\rho =density\ of\ steel =7850 kg/m^3$

$A=area\ of\ cross-section=\frac{\pi }{4}d^2=1.76\times 10^{-4} cm^2$

$T=(88.57)^2\cdot 7850\times 1.76\times 10^{-4}$

$T=10,883 N$

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3 years ago

A 4-kg ball has a momentum of 12 kg∙m/s. what is the ball's speed?

Karolina [17]

M= 4kg
v= ?
momentum = Mv
so
12kgms-¹ = 4kg×v
v= 12÷4 = 3ms-¹

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3 years ago

Read 2 more answers

Please help with 1 and 4

KIM [24]

Number 4 is : a light hour is a measure of time in space used to calculate the length of time between one object to another and one light hour equals 1.079 × 109 kilometers or 1.079e+9

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3 years ago

A ramp is 2.8 m long and 1.2 m high. How much power is needed to push a box up the ramp in 4.6 s with a force of 96 N?

tino4ka555 [31]

Power = work /time

and W = force * dis

W = 96 * 3.046 J = 292.44 J

P = 292.44 / 4.6 = 63.575 watt

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4 years ago

The car was initally traveling at 25 m/s. The car slows with a negative acceleration as shown. How long does it take the car to

Karolina [17]

Answer:

Explanation:

Using one of the equation of motion expressed as v = u+at where;

v is the final velocity = 2.0m/s

u is the initial velocity = 25m/s

a is the acceleration = -a (since the acceleration is negative)

t is the time taken

Substituting the given parameters into the formula above;

2.0 = 25-9.81t

subtract 25 from both sides

2.0 - 25 = 25-9.81t - 25

-23 = -9.81t

Divide both sides by -9.81

-23/-9.81 = -9.81t/-9.81

t = 23.0/9.81

t = 2.35s

<em>Hence it took the car 2.35s to slow to a final velocity of 2.0 m/s</em>

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3 years ago