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3 years ago

Current flowing in a circuit depends on two variables. Identify these variables and their relationship to current.

2 answers:

5 0

Wow ! This question reads like it might have come from one of
Faraday or Maxwell's original laboratory notebooks.

Choice-A is the correct one, when you consider what "conductance"
means. Conductance is just 1/resistance .

So when you see
"A) Current is proportionate to the conductance of the circuit and
precisely proportional to the voltage applied across the circuit."

what it's saying is
"Current is inversely proportional to the resistance of the circuit, and
directly proportional to the voltage applied across the circuit."

If you write the equation for all those words, it looks like

I = V / R

and that's correct.

Tom [10]3 years ago

4 0

Answer: C) Current is inversely proportional to the resistance of the circuit and directly proportional to the voltage applied across the circuit.

Explanation:

<u>Ohm's law</u> states that current is directly proportional to the potential difference across the circuit i.e. voltage.

I ∝ V

⇒ V = I R

where R is the resistance.

Current also depends on resistance offered by the circuit.

So, more the potential difference, more the current but more the resistance offered by the circuit, lesser current would flow.

Current is inversely proportional to the resistance and directly proportional to the voltage across the circuit. Voltage is provided by a cell or a battery. Resistance is offered by the wire and the components connected in the circuit. Sometimes the batteries also have internal resistance which adds up.

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Luden [163]

The Rorschach inkblots and the TAT (Thematic Appreciation Test) both rely on providing the subject with ambiguous visual stimuli and assessing the subject's state of mind using the subject's interpretation of the stimuli.
Both use cards, although not all of the cards are used in the TAT. Moreover, the TAT cards contain sketches, while the Rorschach inkblots contain patterns of ink.

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3 years ago

13. An object, travelling along a straight path, covers 35 m distance in 4 seconds. In next 6

WARRIOR [948]

Answer:

(4) 8.5 m/s

Explanation:

You add both the meters together and both the seconds together and then divide them both.

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3 years ago

Read 2 more answers

You pull two blocks connected by a lightweight string across a horizontal table. Block 1 has a mass of 1.00 kg, and block 2 has

coldgirl [10]

Use google
-Just sayi’n don’t get mad

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2 years ago

a scale model of the solar system where 50 cm represents 1.0x10 to the fifth km is actual distance what would be the dimension o

Fofino [41]

The distance between Mars and the Sun in the scale model would be 1140 m

Explanation:

In this scale model, we have:

$x_1 = 50 cm$ represents an actual distance of

$d_1 = 1.0\cdot 10^5 km$

The actual distance between Mars and the Sun is 228 million km, therefore

$d_2=228\cdot 10^6 km$

On the scale model, this would corresponds to a distance of $x_2$ .

Therefore, we can write the following proportion:

$\frac{x_1}{d_1}=\frac{x_2}{d_2}$

And solving for $x_2$ , we find:

$x_2=\frac{x_1 d_2}{d_1}=\frac{(50)(228\cdot 10^6)}{1\cdot 10^5}=1.14\cdot 10^5 cm = 1140 m$

Learn more about distance:

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3 years ago

A solid conducting sphere with radius R that carries positive charge Q is concentric with a very thin insulating shell of radius

ahrayia [7]

Answer:

The specific question is not stated, however the general idea is given in the attached picture. The electric field in each region can be found by Gauss’ Law.

at r < R:

Since the solid sphere is conducting, the total charge Q is distributed over the surface, and the electric field inside the sphere is zero.

E = 0.

at R < r < 2R:

The electric field can be found by Gauss’ Law as in the attachment. The green pencil shows this exact region.

at 2R < r:

The electric field can again be found by Gauss’ Law, the blue pencil shows the calculations for this region.

Explanation:

Gauss’ Law is straightforward when applied to spheres. The area of the sphere is $A = 4\pi r^2$ , and the enclosed charge is given in the question as Q for the inner sphere, and 2Q for the whole system.

3 0

2 years ago