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3 years ago

Current flowing in a circuit depends on two variables. Identify these variables and their relationship to current.

2 answers:

5 0

Wow ! This question reads like it might have come from one of
Faraday or Maxwell's original laboratory notebooks.

Choice-A is the correct one, when you consider what "conductance"
means. Conductance is just 1/resistance .

So when you see
"A) Current is proportionate to the conductance of the circuit and
precisely proportional to the voltage applied across the circuit."

what it's saying is
"Current is inversely proportional to the resistance of the circuit, and
directly proportional to the voltage applied across the circuit."

If you write the equation for all those words, it looks like

I = V / R

and that's correct.

Tom [10]3 years ago

4 0

Answer: C) Current is inversely proportional to the resistance of the circuit and directly proportional to the voltage applied across the circuit.

Explanation:

<u>Ohm's law</u> states that current is directly proportional to the potential difference across the circuit i.e. voltage.

I ∝ V

⇒ V = I R

where R is the resistance.

Current also depends on resistance offered by the circuit.

So, more the potential difference, more the current but more the resistance offered by the circuit, lesser current would flow.

Current is inversely proportional to the resistance and directly proportional to the voltage across the circuit. Voltage is provided by a cell or a battery. Resistance is offered by the wire and the components connected in the circuit. Sometimes the batteries also have internal resistance which adds up.

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Two uncharged metal spheres, spaced 25.0 cm apart, have a capacitance of 26.0 pF. How much work would it take to move 12.0 nC of

viktelen [127]

Answer:

$W=2.76\times 10^{-6}\ J$

Explanation:

Given that,

The distance between two spheres, r = 25 cm = 0.25 m

The capacitance, C = 26 pF = 26×10⁻¹² F

Charge, Q = 12 nC = 12 × 10⁻⁹ C

We need to find the work done in moving the charge. We know that, work done is given by :

$U=\dfrac{Q^2}{2C}$

Put all the values,

$U=\dfrac{(12\times 10^{-9})^2}{2\times 26\times 10^{-12}}\\\\U=2.76\times 10^{-6}\ J$

So, the work done is $2.76\times 10^{-6}\ J$ .

8 0

3 years ago

If forces acting on an object are unbalanced, which factor may result from an unbalanced force? A.The net force is negative. B.T

bezimeni [28]

Answer:

<h2>A. The net force is negative.</h2>

Explanation:

just took the test :)

4 0

3 years ago

Read 2 more answers

If you ride your bicycle down a straight road for 500m then turn around and ride back, your distance is____ your displacement.

Helen [10]

Answer:

C-less than

Explanation:

Distance is total distance traveled (1000m here if you stop where you started).

Displacement is your final distance from where you started (0m if you stop where you started).

0m<1000m

4 0

3 years ago

Read 2 more answers

A sound wave has frequency 620 Hz and wavelength 10.5 m. What is the speed of sound waves?

olasank [31]

Answer:

Explanation:

A sound wave in a steel rail has a frequency of 620 Hz and a wavelength of 10.5 m. What is the speed of sound in steel? U f = ? S f = 3 x 108 m/s) / 0.06 m 14 so it will be 14

7 0

3 years ago

A 2.93 kg particle has a velocity of (2.98 i hat - 3.98 j) m/s.

cupoosta [38]

Answer:

a) The x and y components of the momentum are $8.731\,\frac{kg\cdot m}{s}$ and $-11.661\,\frac{kg\cdot m}{s}$ , respectively.

b) The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.

Explanation:

a) The vectorial equation of momentum is represented by the following expression:

$\vec p = m\cdot \vec v$ (1)

Where:

$\vec p$ - Vector momentum, measured in kilogram-meters per second.

$m$ - Mass of the particle, measured in kilograms.

$\vec v$ - Vector velocity, measured in meters per second.

If we know that $m = 2.93\,kg$ and $\vec v = 2.98\,\hat{i}-3.98\,\hat{j}\,\,\,\left[\frac{m}{s} \right]$ , then the momentum is:

$\vec p = (2.93)\cdot (2.98\,\hat{i}-3.98\,\hat{j})\,\,\,\left[\frac{kg\cdot m}{s} \right]$

$\vec p = 8.731\,\hat{i}-11.661\,\hat{j}\,\,\,\left[\frac{kg\cdot m}{s} \right]$

The x and y components of the momentum are $8.731\,\frac{kg\cdot m}{s}$ and $-11.661\,\frac{kg\cdot m}{s}$ , respectively.

b) The magnitude and direction of momentum are represented by the following expressions:

$\|\vec p \| = \sqrt{p_{x}^{2}+p_{y}^{2}}$ (2)

$\theta = \tan^{-1}\left(\frac{p_{y}}{p_{x}} \right)$ (3)

Where:

$\|\vec p\|$ - Magnitude of momentum, measured in kilogram-meters per second.

$\theta$ - Direction of momentum, measured in sexagesimal degrees.

If we know that $p_{x} = 8.731\,\frac{kg\cdot m}{s}$ and $p_{y} = -11.661\,\frac{kg\cdot m}{s}$ , then the magnitude and direction of momentum are, respectively:

$\|\vec p\| = \sqrt{\left(8.731\,\frac{kg\cdot m}{s} \right)^{2}+\left(-11.661\,\frac{kg\cdot m}{s} \right)^{2}}$

$\|\vec p\| \approx 14.567\,\frac{kg\cdot m}{s}$

$\theta =\tan^{-1}\left(\frac{-11.661\,\frac{kg\cdot m}{s} }{8.731\,\frac{kg\cdot m}{s} } \right)$

$\theta \approx 306.823^{\circ}$

The magnitude and direction of its momentum are approximately 14.567 kilogram-meters per second and 306.823º.

6 0

3 years ago