Let u = the vertical launch speed.
Neglect air resistance, and g = 9.8 m/s².
At the maximum height of h = 120 cm = 1.2 m, the vertical velocity is zero.
Therefore
(u m/s)² - 2*(9.8 m/s²)*(1.2 m) = 0
u² = 23.52 (m/s)²
u = 4.85 m/s
The time to attain maximum height is one half of the travel time.
If t = time to attain maximum height, then
u - gt = 0
4.85 - 9.8t = 0
t = 4.85/9.8 = 0.495 s
Therefore the travel time is 2*0.0495 = 0.99 s
Answers:
(a) 4.85 m/s
(b) 0.99 s
The next step is -748 divide by -11 is 68 m (answer) the pic got cropped sorry
A windmill produces wind without electricity. wind blows on a windmill and it and that’s how it produces wind. You can put a windmill in anywhere outdoors (ex. Deserts or plains)
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Hope this helped you:)
Answer:
Not balanced
Explanation:
The force pulling the object up is applying less force than the object pulling down, this means the object will move down
Answer:
Explanation:
mass of probe m = 474 Kg
initial speed u = 275 m /s
force acting on it F = 5.6 x 10⁻² N
displacement s = 2.42 x 10⁹ m
A )
initial kinetic energy = 1/2 m u² , m is mass of probe.
= .5 x 474 x 275²
= 17923125 J
B )
work done by engine
= force x displacement
= 5.6 x 10⁻² x 2.42 x 10⁹
= 13.55 x 10⁷ J
C ) Final kinetic energy
= Initial K E + work done by force on it
= 17923125 +13.55 x 10⁷
= 1.79 x 10⁷ + 13.55 x 10⁷
= 15.34 x 10⁷ J
D ) If v be its velocity
1/2 m v² = 15.34 x 10⁷
1/2 x 474 x v² = 15.34 x 10⁷
v² = 64.72 x 10⁴
v = 8.04 x 10² m /s
= 804 m /s