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liberstina [14]
3 years ago
8

Identical satellites X and Y of mass m are in circular orbits around a planet of mass M. The radius of the planet is R. Satellit

e X has an orbital radius of 3R, and satellite Y has an orbital radius of 4R. The kinetic energy of satellite X is Kx.
1) In terms of Kx, the gravitational potential energy of the planet-satellite X system is
(A) -2Kx
(B) -Kx
(C) -Kx/2
(D) Kx/2
(E) 2Kx

2) Satellite x is moved to the same orbit as satellite Y by a force doing work on the satellite. In terms of Kx, the work done on satellite X by the force is
(A) -Kx/2
(B) -Kx/4
(C) 0
(D) +Kx/4
(E) +Kx/2

Show the work for each question.
Physics
1 answer:
GrogVix [38]3 years ago
3 0

Answer:

1) C

2) E

Explanation:

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What effects do coil of wire on a compass after it has been connected to a battery​
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Explanation:

The compass needle moved when the wire was connected to the battery. The important point here is that the needle is affected by the wire only when both ends of the wire are connected to the battery because only at this time is current flowing through the circuit.

8 0
3 years ago
which of the following values can you find by calculating the slope of a graph of velocity versus time position . displacement .
statuscvo [17]
The correct answer is: acceleration.

In fact, the slope of the graph of velocity versus time corresponds to the ratio between the variation of v and the variation of t:
\frac{\Delta v}{\Delta t}
But this is exactly the definition of acceleration: a= \frac{\Delta v}{\Delta t}, so acceleration is the correct answer.
5 0
3 years ago
A light-rail commuter train accelerates at a rate of 1.35 m/s2. How long does it take to reach its top speed of 80.0 km/h, start
Len [333]

Answer:

a) 16.46 seconds.

b) 13.46 seconds

c) 2.67 m/s²

Explanation:

Acceleration = a = 1.35 m/s²

Final velocity = v = 80 km/h = 80\frac{1000}{3600}=22.22\ m/s

Initial velocity = u = 0

Equation of motion

v=u+at\\\Rightarrow 22.22=0+1.35t\\\Rightarrow t=\frac{22.22}{1.35}=16.46\ s

Time taken to accelerate to top speed is 16.46 seconds.

Acceleration = a = -1.65 m/s²

Initial velocity = u = 80 km/h= 80\frac{1000}{3600}=22.22\ m/s

Final velocity = v = 0

v=u+at\\\Rightarrow 0=22.22-1.65t\\\Rightarrow t=\frac{22.22}{1.65}=13.46\ s

Time taken to stop the train from top speed is 13.46 seconds

Initial velocity = u = 80 km/h= 80\frac{1000}{3600}=22.22\ m/s

Time taken = t = 8.3 s

Final velocity = v = 0

v=u+at\\\Rightarrow 0=22.22+a8.3\\\Rightarrow a=\frac{-22.22}{8.3}=-2.67\ m/s^2

Emergency deceleration is 2.67 m/s²

8 0
4 years ago
Energy in motion is _____ energy. potential scientific kinetic
Ket [755]

Answer:

kinetic energy

Explanation:

4 0
4 years ago
Read 2 more answers
In order to determine the coefficients of friction between rubber and various surfaces, a student uses a rubber eraser and an in
Strike441 [17]

Answer:

μs = 0.75

μk = 0.58

Explanation:

From a force diagram:

m*g*sin \theta - Ff=m*a     (1)

N-m*g*cos \theta = 0         (2)

When it starts slipping, friction force is the maximum and acceleration is 0. Replacing these conditions on (1):

m*g*sin \theta - \mu*m*g*cos \theta=0   Solving for μs:

\mu=tan \theta

μs = tan 36.7° = 0.75

When it moves at constant speed, friction force is kinetic friction and acceleration is 0. With these conditions the coefficient is:

μk = tan 30.1° = 0.58

8 0
4 years ago
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