Answer:
Gila Monster is 1.54 times that of Chuckwalla.
Step-by-step explanation:
Given:
Average Length of Gila Monster = 0.608 m
Average Length of Chuckwalla = 0.395 m
We need to find the number of times the Gila monster is as the Chuckwalla.
Solution:
Now we know that;
To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.
framing in equation form we get;
number of times the Gila monster is as the Chuckwalla = 
Rounding to nearest hundredth's we get;
number of times the Gila monster is as the Chuckwalla = 1.54
Hence Gila Monster is 1.54 times that of Chuckwalla.
Answer:
<h2>LCD = 9</h2>
Equivalent Fractions with the LCD
1/3 = 3/9
5/9 = 5/9
Solution:
Rewriting input as fractions if necessary:
1/3, 5/9
For the denominators (3, 9) the least common multiple (LCM) is 9.
LCM(3, 9)
Therefore, the least common denominator (LCD) is 9.
Calculations to rewrite the original inputs as equivalent fractions with the LCD:
1/3 = 1/3 × 3/3 = 3/9
5/9 = 5/9 × 1/1 = 5/9
The rate of change is x2. So, since it's forty, it became 80 because 40x2=80!
Good luck for a good grade!
She my little shawty I know she a rebel
3/8(t+15)
Hope this helped