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kotykmax [81]
3 years ago
15

Can someone please help

Mathematics
1 answer:
mart [117]3 years ago
7 0
B is the right I think
You might be interested in
WILL GIVE BRAINLIEST PLEASE HELP<br> Write the equation and show work. Find 'x" and ' TK'
marishachu [46]

Answer:

x=6

TK=72

Step-by-step explanation:

Because there are two smaller lines drawn in lines TA and AK, it means that the length of TA is the same as AK.

Hence, 6x=4x+12

Subtract 4x from both sides:

6x-4x=4x+12-4x

2x=12

Divide both sides by 2:

\frac{2x}{2}=\frac{12}{2}

x=6

To find TK,

6x+4x+12=10x+12=10\times 6+12=60+12=72

4 0
3 years ago
Been stuck on this for a while man....................
bonufazy [111]

Answer:

2) 6

4) 9

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Select the correct answer.
oee [108]

Answer:

a² + b² = c²

Step-by-step explanation:

Pythagorean theorem: a² + b² = c²

3 0
3 years ago
Rent and other associated housing costs, such as utilities, are an important part of the estimated costs of attendance at colleg
zhenek [66]

Answer:

96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is  [335.89 , 356.10].

Step-by-step explanation:

We are given that a group of researchers at the BYU Off-Campus Housing department want to estimate the mean monthly rent that unmarried BYU students paid during winter 2018.

During March 2018, they randomly sampled 314 BYU students and found that on average, students paid $346 for rent with a standard deviation of $86.

So, the pivotal quantity for 95% confidence interval for the average age is given by;

           P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = average rent paid by 314 BYU students = $346

            s = sample standard deviation = $86

            n = sample of students = 314

            \mu = population mean monthly rent of all unmarried BYU students

So, 96% confidence interval for the population mean monthly rent, \mu is ;

P(-2.082 < t_3_1_3 < 2.082) = 0.96

P(-2.082 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.082) = 0.96

P( -2.082 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.082 \times {\frac{s}{\sqrt{n} } } ) = 0.96

P( \bar X -2.082 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X +2.082 \times {\frac{s}{\sqrt{n} } } ) = 0.96

96% confidence interval for \mu = [ \bar X -2.082 \times {\frac{s}{\sqrt{n} } } , \bar X +2.082 \times {\frac{s}{\sqrt{n} } } ]

                                                = [ 346 -2.082 \times {\frac{86}{\sqrt{314} } } , 346 +2.082 \times {\frac{86}{\sqrt{314} } } ]

                                                = [335.89 , 356.10]

Therefore, 96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].

5 0
4 years ago
Add<br> 6 3/5 + (-6 1/3<br> Enter your answer as a simplified fraction in the box
Sholpan [36]
Okay so basically the answer would be 4/15
8 0
2 years ago
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