Answer:
we only see parts of the lit side as the moon goes around the earth
Explanation:
Unlike the sun, the moon orbits the Earth. This is the reason why we see the <em>different phases of the moon.</em> The reflection of the moon is being illuminated back to us with the help of the sun. So, as the moon circles the Earth, we only see parts of the lit side. Such changes helps us see the moon in different phases such as<em> </em>the <em>Third Quarter, Crescent, New Moon, Full Moon, etc.</em>
For example, during "Full Moon," <em>the moon's entire face is lit up by the sun</em>. Thus, we see the entire moon's lit portion.
Thus, this explains the answer.
SN1 is a substitution reaction
with n being the nucleophilic substitution an 1 represents a unimolecular
reaction. Because the given molecule on the central carbon is sterically
hindered, the rate of carbocation formation is increased dramatically. It will
make the OT (leaving group) to leave and a nucleophile (nucleophilic attack) will
react to the carbocation.
<h3><u>Answer</u>;</h3>
Cu2+, Zn2+, F-, and SO3^2-
<h3><u>Explanation</u>;</h3>
- Hydrolysis is a reaction of a substance or a compound with water.
- Anions such as Cl- and cations such as K+ and Ba2+ of strong acids and bases to not hydrolyze.
- For example; KOH and Ba(OH)2 are strong bases, and HCl is a strong acid.
- All the other ions will have a hydrolysis reaction with water and establish an equilibrium;
Cu2+ + HOH ↔ CuOH^+ + H+
Zn2+ + HOH ↔ZnOH^+ + H+
F- + HOH ↔ HF + OH-
SO3^2- + HOH ↔ HSO3^- + OH-
Answer:
9302 moles of CO contain 5.60×10²⁷ molecules
Explanation:
We solve this with Avogadro's number.
NA = 6.02×10²³
This number states the how many particles are in 1 mol of anything.
1 mol of atoms contains 6.02×10²³ atoms
1 mol of molecules contains 6.02×10²³ molecules.
We apply a rule of three:
6.02×10²³ molecules are contained in 1 mol of CO
Then, 5.60×10²⁷ molecules may be contained in (5.60×10²⁷ . 1) / 6.02×10²³
= 9302 moles
Answer:
mole fraction benzene = 0.62
mole fraction toluene = 0.38
Explanation:
Raoults law for ideal solutions tells us that the totoal vapor pressure of the solution will be given by adding the partial pressures of the components of the solution and the partial pressures are simply given by the product of the component in solution times its pure vapor pressure at the temperature given:
<h2>p total = x₁ P⁰₁ + x₂ P⁰₂</h2>
where x1 and x2 for this solution denote the mole fractions of benzene and toluene and p⁰ ₁, p⁰₂ the vapor pressures of benzene and toluene respectively.
Solving the algebraic equation:
75 x₁ + 22 x₂ = 55
75 x₁ + 22 ( 1- x₁) = 55 (since x₁ + x₂ = 1)
75 x₁ + 22 - 22 x₁ = 55
53 x₁ = 33
x₁ = 0.62
x₂ = 1 - 0.62 = 0.38
