The mass in grams of NH₃ produced from the reaction is 3.4 g
<h3>Balanced equation</h3>
We'll begin by writing the balanced equation for the reaction. This illustrated below:
N₂ + 3H₂ -> 2NH₃
From the balanced equation above,
1 dm³ of N₂ reacted to produced 2 dm³ NH₃
<h3>How to determine the volume of NH₃ produced</h3>
From the balanced equation above,
1 dm³ of N₂ reacted to produced 2 dm³ NH₃
Therefore,
2.24 dm³ of N₂ will react to produce = 2.24 × 2 = 4.48 dm³ of NH₃
<h3>How to determine the mass of NH₃ produced</h3>
We'll begin by obtained the mole of 4.48 dm³ of NH₃. Details below:
22.4 dm³ = 1 mole NH₃
Therefore,
4.48 dm³ = 4.48 / 22.4
4.48 dm³ = 0.2 mole of NH₃
Finally, we shall determine the mass of NH₃ as follow:
- Molar mass of NH₃ = 17 g/mol
- Mole of NH₃ = 0.2 mole
- Mass of NH₃ =?
Mass = mole × molar mass
Mass of NH₃ = 0.2 × 17
Mass of NH₃ = 3.4 g
Learn more about stoichiometry:
brainly.com/question/13196642
#SPJ1
<h3>Hey Mate Here Is Your Answer:- </h3>
The process of forcing liquid at high pressure into rocks, deep holes in the ground, etc. in order to force open existing cracks and take out oil or gas.
<h3>Hope This Helps You ❤️</h3>
1) The time depends on what the lab wanted you to do. It will tell you in the procedure when you are supposed to considered a reaction to be complete and you just measure the time for that to happen.
2) Most text books say that increasing the concentration of one or more reactants will increase the rate of the reaction. To prove this with your data you need to show that when you increased the concentration of one of the reactants, the reaction rate did increase. The results of this experiment are not enough to make a general statement since the experiment was not on a large enough scale to diffidently prove anything. (you could have been testing the one exception or had a error in one of your trials)
I hope this helps. Let me know in the comments if anything is unclear.
(The concentration of one or more of the reactants will increase the rate of the reaction. This is explained through the fact that all reactions require collisions that have certain orientations and a minimum energy level. By increasing the concentration of one or more reactants, you increase the number of collisions which increases the rate since requires collisions in order to occur.) <span />
Answer:
K = 361.369
Explanation:
C2H4(g) + H2O(g) → CH3CH2OH(g)
∴ ΔG°f(298.15K) CH3CH2OH(g) = - 174.8 KJ/mol
∴ ΔG°f(298.15) C2H4(g) = 68.4 KJ/mol
∴ ΔG°f(298.15) H2O(g) = - 228.6 KJ/mol
⇒ ΔG°f(298.15) = - 174.8 - ( - 228.6 + 68.4 ) = - 14.6 KJ/mol
∴ R = 8.314 E-3 KJ/mol.K
∴ T = 298.15 K
⇒ K = e∧(-(-14.6)/((8.314 E-3)(298.15)))
⇒ K = e∧(5.889)
⇒ K = 361.369
