Answer:
(x-4)²/16 + (y-8)²/25 = 1
Step-by-step explanation:
center (h,k): ((4+4)/2 , (3+13)/2) = (4 , 8)
a = 13-8 = 5 c = 8-5 = 3
b = √5²-3² = 4
Equation: (x-h)²/b² + (y-k)²/a² = 1
(x-4)²/16 + (y-8)²/25 = 1
-10 · (-12) = Find the product.
2 answers:
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The standard quantity of metal per ring is 0.57 kilograms.
Step-by-step explanation:
Each ring requires 0.52 kilograms of a special metal.
The allowance for waste is 0.03 kilograms per ring, while the allowance for rejects is 0.02 kilograms per ring.
So, the standard quantity of metal per ring = 0.52 kg of metal required + 0.03 kg of allowance for waste + 0.02 kg of allowance for rejects)
= kilograms.
Hence, the standard quantity of metal per ring is 0.57 kilograms.
Answer: (3, -2)
Step-by-step explanation:
The solution to the system is where the graphs intersect.
