Answer:
it would be A
explanation: if you get $40 dollars and divide it by 4 (which would be equal to giving to 4 people) and then take 3 fourths of it your friend would be left with $10
Answer:
![\frac{2c}{3x^2c}+ \frac{36x^3c}{3x^2c} +\frac{24x^2}{3x^2c} [\tex]Step-by-step explanation:We need to find sum of 2 / 3x^2 +12x and 8 / cSo, solving:[tex](\frac{2}{3x^2} + 12 x ) +\frac{8}{c}](https://tex.z-dn.net/?f=%5Cfrac%7B2c%7D%7B3x%5E2c%7D%2B%20%5Cfrac%7B36x%5E3c%7D%7B3x%5E2c%7D%20%2B%5Cfrac%7B24x%5E2%7D%7B3x%5E2c%7D%20%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EWe%20need%20to%20find%20sum%20of%202%20%2F%203x%5E2%20%2B12x%20and%208%20%2F%20c%3C%2Fp%3E%3Cp%3ESo%2C%20solving%3A%3C%2Fp%3E%3Cp%3E%5Btex%5D%28%5Cfrac%7B2%7D%7B3x%5E2%7D%20%2B%2012%20x%20%29%20%2B%5Cfrac%7B8%7D%7Bc%7D)
Taking LCM of 3x^2 and 1 i.e. 3x^2

C. <2 and <6 is the answer
Answer 1 I think I’m not sure
The probability that a randomly selected carton has a puncture or a smashed corner is 12.6%.
In this problem, the events are:
Event A: Puncture.
Event B: Smashed corner.
The "or" probability is given by:
∩
5% have a puncture, hence 
8% have a smashed corner, hence 
0.4% have both a puncture and a smashed corner, hence
Then:

Therefore, The probability that a randomly selected carton has a puncture or a smashed corner is 12.6%.
Learn more about probability here brainly.com/question/20344684
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