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nydimaria [60]
2 years ago
5

In this particular arithmetic sequence, a7 = 34 and a15 = 74. What is the value of a21?

Mathematics
1 answer:
Karo-lina-s [1.5K]2 years ago
5 0
So i believe its <span> a21 = 109 a21 = 85 a21 = 108 a21 = 104.

So the answer would be 104 

Hope this helps</span>
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How do I get this answer
AveGali [126]

The answer you are looking for would be X=10 because as the bottom triangle has 12 for bottom and 13 from top the top is off by 3 for both of them you just subtract by 3 and 12-3=9 and 13-3=10 plz give brainliest

4 0
3 years ago
A school bought $548 in basketball equipment and uniforms costing $29.50 each. The total cost was $2,023. Write an equation you
VladimirAG [237]
Equation:
Total cost = fixed costs + variable costs
2023 = 548 + 29.50x

Solution:
2023 - 548 = 29.50x
(2023 - 548)/29.50 = x
50 = x
3 0
3 years ago
(Please answer ASAP) (Thank you &lt;3)<br><br> What is the relative frequency for Group A.
frosja888 [35]

The answer is D, I think so

8 0
2 years ago
Read 2 more answers
Trying to find volume of a right circular cone.
viva [34]

Volume of the cone is 117.5 π ft³

<u>Step-by-step explanation:</u>

Lateral area of the cone = πrs

s is the slant height = 15 ft

From the above formula, we can find the radius as, 5 ft.

Volume of the cone = π r² h/3

s = √ (5²+ h²)

Squaring on both sides, we will get,

s² = 15² = (5² + h²)

 15² - 5² = h²

225 - 25 = 200 = h²

h = √200 = 14.1 ft

Volume = π × 5² × 14.1  / 3 = 117.5 π ft³

8 0
2 years ago
Solve x2 + 14x + 17 = –96 for x
jarptica [38.1K]

For this case we have to:

Given the quadratic equation of the form:

ax ^ 2 + bx + c = 0

The roots are given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

If we have: x ^ 2 + 14x + 17 = -96

We can rewrite it in the following way:

x ^ 2 + 14x + 17 + 96 = 0\\x ^ 2 + 14x + 113 = 0

Where:

a = 1\\b = 14\\c = 113

Where we have:

x = \frac {-14 \pm \sqrt {(14) ^ 2-4 (1) (113)}} {2 (1)}

x = \frac {-14 \pm \sqrt {(196-452)}} {2}

x = \frac {-14 \pm \sqrt {-256}} {2}

By definition: \sqrt {-1} = i

x = \frac {-14 \pm \sqrt {256} i} {2}

x = \frac {-14 \pm16i} {2}

x = \frac {-14} {2} \pm \frac {16i} {2}

x = -7 \pm8i

Thus, the roots are given by imaginary numbers:

x_ {1} = - 7 + 8i\\x_ {2} = - 7-8i

Answer:

x_ {1} = - 7 + 8i\\x_ {2} = - 7-8i


5 0
3 years ago
Read 2 more answers
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