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Rama09 [41]
3 years ago
13

Ax + 3x = bx + 5 solve for x

Mathematics
1 answer:
aniked [119]3 years ago
5 0

Answer:

Step-by-step explanation:

hello :

Ax + 3x = bx + 5

Ax + 3x-bx = bx-bx + 5

x(A+3-b) =5

x= 5/(A+3-b)

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Someone please help me it's worth 35 points
Zigmanuir [339]
Question 1)
I assume it asks about the circumference (of only the circle arc)
C=r*2*pi
r=2
-> C=4pi

1 Quarter only of the circle: C/4=pi=3.1

if it's the perimeter of the shape then you need to add the two 2in sides

C=3.1+2*2=7.1

2)
C=r*2*pi, but not a full circle, only semi-> divide by 2-> C=r*pi
r=30
C=30pi=94.2

3)
the radius of the semicircle is 6/2=3mm
semicircle C=r*pi=3pi

add the rectangle perimeter
3pi+2*3+6=12+3pi=21.4

4)
C=2r*pi
insert 2r=d=12
C=12pi=37.7

5)
C=2r*pi
r=10
C=20*pi~62.8

3 rotations of the wheel->
distance=C*3=188.4
4 0
3 years ago
Each cone of the hourglass has a height of 15 millimeters. The total height of the sand within the top portion of the hourglass
irina1246 [14]
We have to calculate the height of a cylinder : h2 = ( 45 - 2 · 15 )/ 2 = 15 / 2 = 7.5 mm
Volume of the bottom of the hourglass:V = 1/3 r² π h1 + r² π h2 = = 1/3 · 6² · 3.14 · 15 + 6² · 3.14 · 7.5 = = 1/3 · 36 · 3.14 · 15 + 36 · 3.14 · 7.5 = = 565.2 + 847.8 = 1,413 mm³The rate is 10 π mm³/ sec = 31.4 mm³/secTime = 1,413 : 31.4 = 45 sec.Answer: It will take 45 seconds.

8 0
3 years ago
−104=4x−4(2x+16)<br> I need a whole number i keep messing up
kotykmax [81]

Answer:

x=10

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find two positive numbers satisfying the given requirements. The product is 216 and the sum is a minimum. (No Response) (smaller
fgiga [73]

Answer:

x1=\sqrt{216} \  and \ y1=\ \sqrt{216}

Step-by-step explanation:

Let the first number is x1 and other number is y1 then

x1 * y1 =216

Therefore

y1=\frac{216}{x1}

also there sum is

s1 =x1+y1....Eq(1)

Putting the value of y1  in the previous equation

s1\ =x1 + \frac{216}{x1}........Eq(2)

Differentiate the the Eq(2) with respect to x1 we get

\frac{ds1}{dx1} \ =\ 1+216*\frac{1}{-x1^{2} }

\frac{ds1}{dx1} \ =\ 1-\frac{216}{x1^{2} }\ =\ 0

{x1^{2} }\ =\ 216\\  x1=\sqrt{216}

Putting the value of X1 in Eq(1) we get

y1=\frac{216}{\sqrt{216} } \\y1=\frac{216*\sqrt{216} }{216} \\y1=\ \sqrt{216}

So x1=\sqrt{216} \  and \ y1=\ \sqrt{216}

6 0
4 years ago
Which expression is equivalent to 2(4 + x + 6y) + 3(5 + 3x + y)
vekshin1

Answer:11x + 15y + 23

Step-by-step explanation:

5 0
3 years ago
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