Answer:
senior citizen cost $4
children cost $7
Step-by-step explanation:
The question is not complete
<em>Brenda's school is selling tickets to a spring musical. On the first day of ticket sales the school sold 3 senior citizen tickets and 9 child ... The school took in $67.00 on the second day by selling 8 senior citizen tickets and 5 child tickets. What is the price each of one senior citizen ticket and one child ticket?</em>
Given data
let senior citizens be x
and children be y
so
3x+9y= 75--------------1
on the second day
8x+5y= 67------------2
solve 1 and 2 above
3x+9y= 75 X8
8x+5y= 67 X3
24x+72y=600
-24x+15y=201
0x+57y= 399
divide both sides by 57
y= 399/57
y= $7
put y= 7 in eqn 1 above
3x+9*7= 75
3x+63= 75
3x=75-63
3x=12
x= 12/3
x= $4
25% of 30 = 7.5
Hope this helps idk if it does tho
Answer:
Basketball all the way!
Step-by-step explanation:
Answer:
9 kilograms is = 9000 grams
9 kilograms=317.466 ounces
Step-by-step explanation:
Answer:
3,750 cars.
Step-by-step explanation:
We are given that the equation:
Models the relationsip between <em>y</em>, the number of unfilled seats in the stadium, and <em>x</em>, the number of cars in the parking lot.
We want to determine the number of cars in the parking lot when there are no unfilled seats in the stadium.
When there are no unfilled seats in the stadium, <em>y</em> = 0. Thus:
Solve for <em>x</em>. Subtract 9000 from both sides:
Divide both sides by -2.4:
So, there will be 3,750 cars in the parking lot when there are no unfilled seats in the stadium.
