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ArbitrLikvidat [17]
3 years ago
6

Evaluate 7C3 OA) 25 O B) 45 OC) 35 OD) 20

Mathematics
2 answers:
SpyIntel [72]3 years ago
8 0

Answer:

C) 35

Step-by-step explanation:

^7C_3 \\  =   \frac{7!}{3!(7 - 3)!}  \\=   \frac{7!}{3! \: 4!}   \\ =   \frac{7 \times 6 \times 5 \times 4!}{3 \times 2 \times 1 \times   4!}  \\ =   \frac{7 \times 6 \times 5 \times 4!}{3 \times 2 \times 1 \times   4!}    \\ = 35 \\ \huge \red{ \boxed{  \therefore \: ^7C_3  = 35}}

Morgarella [4.7K]3 years ago
8 0

Answer:

C=35

Step-by-step explanation:

⁷C₃

These is combination

using the rule it states that

ⁿCₐ= n!/(n-a)!a!

so therefore ⁷C₃= 7!/(7-3)!3! = 7!/4!3!=7x6x5x4x3x2x1/{(4x3x2x1)x(3x2x1)}

4x3x2x1 cancels itself as it appears up and down

7x6x5/6

6 cancels each itself as it appears up and down

7x5 = 35

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saul85 [17]

We have expression -5 < x - 4 \geq 1 that renders the system of inequalities,

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Which can be simplified to,

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Hope this helps.

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