All categories

2 years ago

6. At what intervals is the function g(x) shown below increasing and/or decreasing?

Mathematics

1 answer:

gizmo_the_mogwai [7]2 years ago

4 0

Decreasing [-8, -4] increasing [-1, 2]

(look at the slopes)

You might be interested in

Can you help me plz

Alex73 [517]

9514 1404 393

Answer:

y = x + 4

Step-by-step explanation:

To find the constant in the equation, look in the table for the value of y when x=0. That value is 4, so ...

y = x + 4

6 0

2 years ago

Evaluate the integral of the quantity x divided by the quantity x to the fourth plus sixteen, dx . (2 points) one eighth times t

Anika [276]

Answer:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

Step-by-step explanation:

Given

$\int\limits {\frac{x}{x^4 + 16}} \, dx$

Required

Solve

Let

$u = \frac{x^2}{4}$

Differentiate

$du = 2 * \frac{x^{2-1}}{4}\ dx$

$du = 2 * \frac{x}{4}\ dx$

$du = \frac{x}{2}\ dx$

Make dx the subject

$dx = \frac{2}{x}\ du$

The given integral becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{x}{x^4 + 16}} \, * \frac{2}{x}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{1}{x^4 + 16}} \, * \frac{2}{1}\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

Recall that: $u = \frac{x^2}{4}$

Make $x^2$ the subject

$x^2= 4u$

Square both sides

$x^4= (4u)^2$

$x^4= 16u^2$

Substitute $16u^2$ for $x^4$ in $\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{x^4 + 16}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16u^2 + 16}} \,\ du$

Simplify

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \int\limits {\frac{2}{16}* \frac{1}{8u^2 + 8}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{2}{16}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

In standard integration

$\int\limits {\frac{1}{u^2 + 1}} \,\ du = arctan(u)$

So, the expression becomes:

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}\int\limits {\frac{1}{u^2 + 1}} \,\ du$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(u)$

Recall that: $u = \frac{x^2}{4}$

$\int\limits {\frac{x}{x^4 + 16}} \, dx = \frac{1}{8}*arctan(\frac{x^2}{4}) + c$

4 0

2 years ago

A binomial distribution has p = 0.05 and n = 50. what is the mean of this distribution?

Kruka [31]

2.5 is the mean of this distribution.

What is the distribution's mean?

The expected value, commonly known as the mean of a statistical distribution with a continuous random variable, is calculated by integrating the product of the variable's probability as described by the distribution.
The lowercase Greek letter mu () stands for the expected value. A probability of 50% equals zero standard deviations, and the mean is in the middle of the normal distribution.

Given: p = 0.05 and n= 50

Mean of the binomial distribution = n×p = 50 × 0.05 = 2.5

Therefore, option a is the correct answer. Other options are incorrect because these are irrelevant.

Learn more about binomial distribution

brainly.com/question/14565246

#SPJ4

7 0

1 year ago

What is the piecewise function for g(x)=2|x-1|+2

Scorpion4ik [409]

Hope this answer helps you

7 0

3 years ago

Find the correct value of x

bearhunter [10]

Answer: x = 20

Step-by-step explanation:

Right angle = 90

90 - 47 = 43

43 - 3 = 40

40/2 = 20

3 0

2 years ago