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Greeley [361]
3 years ago
11

Is it possible to find the product of two mixed numbers by multiplying the whole number parts together, then multiplying the two

fractional parts together,and finally adding the two products? Use an example
Mathematics
1 answer:
sveticcg [70]3 years ago
7 0
No, an example would be 1 1/2* 1 1/2 or 3/2*3/2 if you did it the way mentioned above you would get 1*1+1/2*1/2 which is 1 1/4, however if we multiply correctly, 3/2*3/2 we actually get 9/4 which is equal to 2 1/4.
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Select the correct ratios.
Goshia [24]
65:100 because there are 65 girls and then 65 girls + 35 boys = 100 total students
4 0
2 years ago
PLEASEE HELPP ME IM DESPERATE​
miss Akunina [59]

Answer:

I can help with Q "4" as -

It uses triangle congruence test -  here we use - SAS, as

one side is equal as it is given

both the  angles are 90 degree

and they share a same side

so -

8x = 6x + 5

8x - 6x = 5

2x = 5

x = 2.5

RU = 6x+ 5 = 6 (2.5) + 5 = 20

( I am not so sure but I think this is the answer )

3 0
3 years ago
Two pounds of grapes cost 6$ what number belongs in the most right empty cell?
sdas [7]

Answer:

Table shown below

Step-by-step explanation:

Table shown below

To solve this problem let's use proportions.

If 2 pounds of grapes cost $6, half the amount will cost half the dollars, so the last row will have $3 in the price

For the second row, we know the price is $1, that is, one-sixth of the original given price. It should correspond to one-sixth of the amount of grapes or 2/6 pounds.

Simplifying the fraction, we get 1/3 or 0.33 pounds

6 0
3 years ago
The product of two mixed numbers x and y is 10. If x= _ 2/3 and y=_ 3/4 ,<br> find x and y?
Akimi4 [234]

Answer:

  • x = 2 2/3
  • y = 3 3/4

Step-by-step explanation:

There may be other ways to do this. Here's the approach I took. Let the integer part of x be represented by "a", and the integer part of y be represented by "b". Now, we have ...

  (a +2/3)(b +3/4) = 10

Multiplying by 12, this becomes ...

  (3a +2)(4b +3) = 120

There are only 16 divisors of 120, so they can be easily enough checked one at a time.

  120 = 1·120 = 2·60 = 3·40 = 4·30 = 5·24 = 6·20 = 8·15 = 10·12

Of these divisors, the ones that are of the form 3a+2 are ...

  2, 5, 8, 20 . . . . a=0, 1, 2, 6

The ones that are of the form 4b+3 are ...

  3, 15 . . . . b = 0, 3

The factor pair that consists of a number on the first list and a number on the second list is ...

  120 = 8·15

corresponding to a=2 and b=3. So, the mixed numbers you want are ...

  x = 2 2/3

  y = 3 3/4

_____

<em>Check</em>

  (2 2/3)·(3 3/4) =2·3 +2·3/4 +2/3·3 +2/3·3/4 = 6 +6/4 +2 +2/4 = 8+8/4 = 10

6 0
3 years ago
jeff uses 3 fifth - size strip to modek 3/5. he wants to use tenth-size strip to model an equivalent fraction. how many tenth-si
guapka [62]
An equivalent fraction? So.. the fraction has to be equivalent to 3/5, correct?
One question, what do you mean by "tenth-size strip"?
Sorry but this question isn't clear enough.
Sorry :/
6 0
4 years ago
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