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iren [92.7K]
4 years ago
14

The dress store is having a sale where all merchandise is 1/4 off. a women buys $42 of merchandise at the sale price.

Mathematics
1 answer:
OlgaM077 [116]4 years ago
4 0

Alright, lets get started.

Suppose women had to pay x $ at regular price.

As we know, the sale is 1/4 off.

It means she saves x * 1/4 = x/4

So, women need to pay = regular price - what she saves

women need to pay = x - x/4 = 3 x / 4 that is equal to 42 (given in question)

3x / 4 = 42

Multiplying 4 in both sides.

3x / 4 * 4 = 42 * 4

3 x = 168

Dividing 3 in both sides

3 x / 3 = 168/ 3

x = 56

she have had to pay 56 $ at the regular price : Answer

Hope it will help :)

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You have 6 pints of glaze. It takes 7/8 of a pint to glaze a bowl and 9/16 of a pint to glaze a plate.
son4ous [18]

Answer:

a. How many bowls could you glaze?

6 bowls

How many plates could you glaze?

10 plates

b. You want to glaze 5 bowls, and then use the rest for plates.

How many plates can you glaze?

2 plates

How much glaze will be left over?

8/9 of glaze would be left

c. How many of each object could you glaze so that there is no glaze left over? Explain how you found your answer.

4 4/23 bowls and 4 4/23 plates

Step-by-step explanation:

We are told in the question

Number of pints of glaze = 6 pints

Number of pints to glaze a bowl= 7/8 of pint

Number of pints to glaze a plate = 9/16 of a pint

a.

How many bowls could you glaze?

7/8 pint = 1 bowl

6 pints = x

Cross Multiply

x = 6 pints/ 7/8

= 6 × 8/7

= 48/7

= 6.8571428571 bowls

We can only glaze whole numbers of a bowl, hence, we can only glaze 6 bowls

How many plates could you glaze?

9/16 pint = 1 bowl

6 pints = y

y = 6 pints/ 9/16

= 6 × 16/9

= 10.666666667 plates

We can only glaze whole number of a plate, hence, we can only glaze 10 plates

b. You want to glaze 5 bowls, and then use the rest for plates.

1 bowl = 7/8 pints

5 bowls = z

Cross Multiply

z = 5 × 7/8pints

= 4 3/8 pints of glaze would be used for bowls

How many plates can you glaze?

The rest is for plates, hence:

The amount of glaze left for plates is calculated as:

6 pints - 4 3/8

1 5/8 pints of glaze would be left over to glaze plates.

So therefore,

9/16 pints = 1 plate

1 5/8 pints =

= 2 8/9

Hence we can only glaze 2 plates

How much glaze will be left over?

2 8/9 pints - 2 pints

= 8/9 pints of glaze.

c. How many of each object could you glaze so that there is no glaze left over?

We have 6 pints of glaze

Number of pints to glaze a bowl= 7/8 of pint

Number of pints to glaze a plate = 9/16 of a pint

Let the number of each objects be represented by x

7/8 × x + 9/16 × x = 6 pints

= 4 4/23 bowls and 4 4/23 plates

3 0
3 years ago
PLEASE HELP WITH GRAPH LAST QUESTION I NEED ​
SVETLANKA909090 [29]

Answer:

\sf g(x) = -1(x+3)^2 -2

Explanation:

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the graph is translated 3 units to the left and 2 units down.

vertex: (-3,-2) point: (-1,-6)

\sf so \ new \ graph :

\sf y = a(x-h)^2 +k

\sf -6 = a(-1-(-3))^2 -2

\sf -6 = 4a -2

\sf 4a = -4

\sf a = -1

\sf equation:

\sf y = a(x-h)^2 +k

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DaniilM [7]

Answer:

the ans is 9/10

Step-by-step explanation:

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Find the minimum and maximum value of the function on the given interval by comparing values at the critical points and endpoint
Kitty [74]

Answer:

maximum: y = 1

minimum: y = 0.

Step-by-step explanation:

Here we have the function:

y = f(x) =  √(1 + x^2 - 2x)

we want to find the minimum and maximum in the segment [0, 1]

First, we evaluate in the endpoints, which are 0 and 1.

f(0)  =√(1 + 0^2 - 2*0) = 1

f(1) = √(1 + 1^2 - 2*1) = 0

Now let's look at the critical points (the zeros of the first derivate)

To derivate our function, we can use the chain rule:

f(x) = h(g(x))

then

f'(x) = h'(g(x))*g(x)

Here we can define:

h(x) = √x

g(x) = 1 + x^2 - 2x

Then:

f(x) = h(g(x))

f'(x)  =  1/2*( 1 + x^2 - 2x)*(2x - 2)

f'(x) = (1 + x^2 - 2x)*(x - 1)

f'(x) = x^3 - 3x^2 + x - 1

this function does not have any zero in the segment [0, 1] (you can look it in the image below)

Thus, the function does not have critical points in the segment.

Then the maximum and minimum are given by the endpoints.

The maximum is 1 (when x = 0)

the minimum is 0 (when x = 1)

7 0
3 years ago
Help please here is a picture:
Ivahew [28]

Answer:

<em>2 1/3, 2 1/4, 2 3/7</em>

Step-by-step explanation:

<u>Mixed Fractions</u>

Mixed fractions are made of an integer part followed by a proper fraction.

Some examples of mixed fractions are:

3 1/2, -4 5/8, 2 2/3

Between two consecutive integers a and a+1, there are infinitely many fractions. The centered number is a 1/2. Any number with its improper fraction part less than 1/2 is closer to a than to a+1.

In our problem, Jayne bought between 2 and 3 pounds of granola. We need to provide a mixed number that is closer to 2 pounds than to 3 pounds.

We can select any number with integer part 2 and a proper fraction less than 1/2.

Examples could be :

2 1/3, 2 1/4, 2 3/7

All of them are less than 2.5

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3 years ago
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