There are 0.0214 mol Cs in 1.29×10²² atoms Cs.
Use <em>Avogadro’s number</em> to convert atoms of Cs to moles of Cs.
Moles of Cs = 1.29×10²² atoms Cs × (1 mol Cs /6.022 × 10²³ atoms Cs) = 0.0214 mol Cs
I'm pretty sure the answer is Pyroclastic flow
<span>Calcium crystal has a face center cubic (FCC) structure. For FCC structure,
relation between edge length (a) and radius (r) is
a = 2</span>√2 r
<span>Given: r = 180 pm
Therefore, a = 2</span>√2 180
<span> = 2 x 1.141 x 180
= 410.76 pm
</span><span>The length of the edge of the Ca unit cell is 410.76 pm.</span><span>
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