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leonid [27]
3 years ago
6

Consider the half reactions below for a chemical reaction.

Chemistry
1 answer:
ladessa [460]3 years ago
7 0

Answer:

Option A:

Zn(s) + Cu^(2+) (aq) → Cu(s) + Zn^(2+)(aq)

Explanation:

The half reactions given are:

Zn(s) → Zn^(2+)(aq) + 2e^(-)

Cu^(2+) (aq) + 2e^(-) → Cu(s)

From the given half reactions, we can see that in the first one, Zn undergoes oxidation to produce Zn^(2+).

While in the second half reaction, Cu^(2+) is reduced to Cu.

Thus, for the overall reaction, we will add both half reactions to get;

Zn(s) + Cu^(2+) (aq) + 2e^(-) → Cu(s) + Zn^(2+)(aq) + 2e^(-)

2e^(-) will cancel out to give us;

Zn(s) + Cu^(2+) (aq) → Cu(s) + Zn^(2+)(aq)

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What type of reaction is shown below: Br2 + Kl 12 + KBr​
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Answer:Chemical reaction

Explanation:

The main concept that must be applied to determine the coefficients (amount of each item) is that there must be equal amounts of each element on each side of the equation. We are not destroying or creating new atoms. In this case, the unbalanced reaction formula is:

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There are a two problems we need to solve before it will be balanced:

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r

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I

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K

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I

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There is one mole of Iodine atoms on the left, and two on the right. To fix this, we add a coefficient of two to the

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B

r

2

+

2

K

I

=

2

K

B

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+

I

2

Bonus step: We can also put ones in front of the coefficient-less species. This is like changing a phrase from "an apple" to "1 apple". It is the exact same thing, but makes it a little more clear sometimes. This would like like this:

1

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Can you see that there is now an equal amount of each element on each side of the equation? That means that it is balanced.

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