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Elza [17]
4 years ago
14

If the atomic radius of a calcium crystal is 180 pm, what is the length of the edge of the unit cell? (the calcium crystal forms

Chemistry
1 answer:
My name is Ann [436]4 years ago
4 0
<span>Calcium crystal has a face center cubic (FCC) structure. For FCC structure,
relation between edge length (a) and radius (r) is
                                                       a = 2</span>√2 r
<span>Given: r = 180 pm
Therefore, a = 2</span>√2 180
<span>                     = 2 x 1.141 x 180
                     = 410.76 pm

</span><span>The length of the edge of the Ca unit cell is 410.76 pm.</span><span>

 </span>
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HELP 20 points!
monitta

Answer:

The limiting reagent is the reactant that is completely used up in a reaction, and thus determines when the reaction stops. ... The limiting reagent is the one that is totally consumed; it limits the reaction from continuing because there is none left to react with the in-excess reactant.

Explanation:

The limiting reagent is the reactant that is completely used up in a reaction, and thus determines when the reaction stops. ... The limiting reagent is the one that is totally consumed; it limits the reaction from continuing because there is none left to react with the in-excess reactant.

5 0
3 years ago
How do I study Chemistry efficiently?
TEA [102]
Review and Study Material Before Going to
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Seek Understanding.

Take Good Notes.

Practice Daily.

Take Advantage of Lab Time.

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5 0
3 years ago
A 4.36-g sample of an unknown alkali metal hydroxide is dissolved in 100.0 mL of water. An acid-base indicator is added, and the
BARSIC [14]

Answer:

Rb+

Explanation:

Since they are telling us that the equivalence point was reached after 17.0 mL of   2.5 M HCl were added , we can calculate the number of moles of HCl which neutralized our unknown hydroxide.

Now all the choices for the metal cation are monovalent, therefore the general formula for our unknown is XOH and  we know the reaction is 1 equivalent acid to 1 equivalent base. Thus we have the number of moles, n,  of XOH and from the relation n = M/MW we can calculate the molecular weight of XOH.

Thus our calculations are:

V = 17.0 mL x 1 L / 1000 mL = 0.017 L

2.5 M HCl x 0.017 L = 2.5 mol/ L x 0.017 L = 0.0425 mol

0.0425 mol = 4.36 g/ MW XOH

MW of XOH = (atomic weight of X + 16 + 1)

so solving the above equation we get:

0.0425 = 4.36 / (X + 17 )

0.7225 +0.0425X = 4.36

0.0425X = 4.36 -0.7225 = 3.6375

X = 3.6375/0.0425 = 85.59

The unknown alkali is Rb which has an atomic weight of 85.47 g/mol

6 0
4 years ago
the existence of a vacancy in a crystal decreases the energy of the material i. not enough information to determine ii. false ii
enot [183]

iii. True. The existence of a vacancy in a crystal decreases the energy of the material.

One of the scientific disciplines called crystallography examines how the atoms in a solid crystal are arranged. When molecules are linked together in a regular way, these crystals are created.

The mechanical, physical, and optical properties of a material can alter when crystal flaws are present. The strength of the material can be impacted by a flaw.

An irregularity in the atoms' regular geometrical arrangement within a crystalline material is referred to as a crystal defect. These flaws are caused by the solid being deformed, cooling quickly from a high temperature, or being exposed to high-energy radiation (such as X-rays or neutrons). because the vacancy cause defects and the crystal structure is disturbed this causes a decrease in energy.

To know more about vacancy visit the link:

brainly.com/question/14937309?referrer=searchResults

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6 0
1 year ago
What is the volume of 0.120 g of C2H2F4<br> vapor at 0.970 atm and 22.4°C?<br> Answer in units of L.
ludmilkaskok [199]

Answer:

V= 0.031L

Explanation:

P= 0.97atm, V= ?, n= 0.12/98 =0.00122mol, R= 0.082, T= 22.4+273= 295.4

Applying

PV=nRT

0.970×V = 0.00122×0.082×295.4

Simplify the above equation

V= 0.031L

6 0
3 years ago
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