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Elza [17]
4 years ago
14

If the atomic radius of a calcium crystal is 180 pm, what is the length of the edge of the unit cell? (the calcium crystal forms

Chemistry
1 answer:
My name is Ann [436]4 years ago
4 0
<span>Calcium crystal has a face center cubic (FCC) structure. For FCC structure,
relation between edge length (a) and radius (r) is
                                                       a = 2</span>√2 r
<span>Given: r = 180 pm
Therefore, a = 2</span>√2 180
<span>                     = 2 x 1.141 x 180
                     = 410.76 pm

</span><span>The length of the edge of the Ca unit cell is 410.76 pm.</span><span>

 </span>
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The ph of a fruit juice is 3.2. find the hydronium ion​ concentration, left bracket upper h 3 upper o superscript plus right bra
melomori [17]

pH is referred to as the scale to describe the hydronium ion concentration of a

solution. It is used to measure the acidity or basicity of a solution. pH of an acidic solution is less than 7, a neutral solution is 7, and a basic solution is greater than 7.

pH can be calculated using the formula:

pH = - log [H_{3}O^{+}]

Given the pH of solution is 3.2.

Finding out the concentration of hydronium ion from pH.

pH = - log[H_{3}O^{+}]

3.2 = - log [H_{3}O^{+}]

[H_{3}O^{+}] = 10^{-3.2}

[H_{3}O^{+}] =   6.3 * 10^{-4} M

Therefore, the hydronium ion concetration of the solution is 6.3 * 10^{-4} M

3 0
3 years ago
How many moles of N2O3 contain 2.55 × 1024 oxygen atoms
Varvara68 [4.7K]
1mol   ------------   3×6,02×10²³ oxygen atoms
x          ------------   2,55×10²⁴

x = 2,5×10²⁴ × 1mol / 3×6,02×10²³ ≈ 0,138*10 mol = 1,38mol

6 0
3 years ago
The following table lists molecular weight data for a polypropylene material. Molecular Weight Range (g/mol) xi wi
nikklg [1K]

Answer:

a) the number-average molecular weight is 32,400 g/mol

b) the weight-average molecular weight is 36,320 g/mol

c) the degree of polymerization is 770

Explanation:

Given the data in the question;

Molecular                  Mean        Number      Weight      Number        Weight

weight                                                                             average         average

(g/mol)                    Mi(g/mol)         xi                wi          xiMi                  wiMi

8,000-16,000            12,000        0.07           0.03         840                360

16,000-24,000          20,000       0.15           0.09         3000              1800

24,000-32,000         28,000       0.26           0.21          7280              5880

32,000-40,000         36,000       0.27           0.27         9720               9720

40,000-48,000         44,000       0.18            0.28         7920              12320

48,000-56,000         52,000       0.07           0.12          3640              6240

∑                                                                                Mn=32,400     Mw=36,320

so;

a)  the number-average molecular weight

Mn = ∑Mixi

so from the table above; summation of Row Mixi

Mn = ∑Mixi = 32,400

Therefore, the number-average molecular weight is 32,400 g/mol

b) the weight-average molecular weight

Mw = ∑Miwi

so from the table above; summation of Row Miwi

Mw = ∑Miwi = 36,320

Therefore, the weight-average molecular weight is 36,320 g/mol

c) the degree of polymerization

the degree of polymerization of polypropylene can be determined using number-average molecular and repeat unit molecular weight.

now, for polypropylene { CH₂ = CH - CH₃ }

the repeat unit consist of 3 carbon atoms and 6 hydrogen atoms

given that;

Atomic weight of Carbon mC = 12.01 g/mol and

Atomic weight of  Hydrogen mH = 1.008 g/mol

now we find the repeat unit molecular weight of polypropylene

m = nCmC + nHmH

where n is the number of repeat of atoms

so we substitute

m = ( 3 × 12.01) + ( 6 × 1.008)

m = 36.03 + 6.048

m = 42.078 g/mol

now we calculate the degree of polymerization;

DP = Mn / m

so we substitute

DP = 32,400 / 42.078

DP = 769.9985 ≈ 770

Therefore,  the degree of polymerization is 770

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3 years ago
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They break up and become only positive energy
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3 years ago
What is the mass of 3.0 x 1023 atoms of neon
Xelga [282]
1 mole =6.0 * 10^23 atoms
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0.5 moles = 10.09 grams
8 0
3 years ago
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