If the atomic radius of a calcium crystal is 180 pm, what is the length of the edge of the unit cell? (the calcium crystal forms

1 answer:

4 0

Calcium crystal has a face center cubic (FCC) structure. For FCC structure,
relation between edge length (a) and radius (r) is
a = 2√2 r
Given: r = 180 pm
Therefore, a = 2√2 180
 = 2 x 1.141 x 180
= 410.76 pm

The length of the edge of the Ca unit cell is 410.76 pm.

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