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mamaluj [8]
4 years ago
15

Which values, when placed in the box, would result in a system of equations with no solution? Check all that apply.

Mathematics
1 answer:
s2008m [1.1K]4 years ago
6 0
Y = -2x + 4
6x + 3y = 6x + 3(-2x + 4) = 6x - 6x + 12 = 12
⇒ y = -2x + 4 == 6x + 3y = 12 ⇒ invinite solutions: 12
⇒ no solutions -12, -4, 0, 4



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PLEASE HELP! WILL MARK BRAINLIEST!
AfilCa [17]
Number 3 is the correct answer 
5 0
4 years ago
Show your work for factoring or quadratic formula:
lutik1710 [3]
First, I'd simplify this problem by dividing every term by 2:

x^4 - 4x^3 + 5x^2 - 4x + 4 = 0

Then I'd think of the possible factors of that constant term, 4:  They would be plus or minus 1, plus or minus 2, or plus or minus 4.

Let's try x = -4 as a possible root.  Setting up and using synthetic division:

      ____________________
-4  /   1   -4   5    -4    4
              -4   32
     ----------------------------
         1    -8  37

This result is not helpful.  So, try the possible root +4 instead:
       ________________
+4  /   1   -4   5    -4    4
                4    0   20   64
       ----------------------------
         1     0    5    16   68             4 is not a root because the remainder   
                                                    (68) is not zero.

Try x = 2:

       ________________
+2  /   1   -4   5    -4    4
                2   -4    2    -40
       ----------------------------
          1    -2   1    -2    0

2 is a root because the remainder is zero.

Continue this process until you've found the other 3 roots.

Hint:  Try  the possible root x = -2 with the following coefficients:

     ____________
-2 /  1   -2   1   -2

    ---------------------
5 0
3 years ago
The price of a pair of shoes and a shirt before tax is $24. There is a 7% sales tax on the shoes and the shirt. How much total m
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6 0
3 years ago
Read 2 more answers
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saul85 [17]
I think the answer would be 2 different groups.
3 0
3 years ago
Read 2 more answers
Stephon is buying some snacks for his siblings at a convenience store. He wants to buy at least 6 items, but he has only $12 in
Irina18 [472]

Answer:

Stephon can buy total 4 chips bag and 2 candy bar

Given as :

The money which Stephon has in his pocket = $ 12

The cost of one chips bag = $ 2.25

The cost of one candy bar = $ 1.50

The total number of items he can buy = 6

So, Let the number of chips bag he can buy = x

∴ The number of candy bar he can buy = 6 - x

Now, according to question

The number of chips bag×The cost of one chips bag + The number of candy bar×The cost of one candy bar = $ 12

Or, x × $ 2.25 + (6-x) × $ 1.50 = $ 12

Or,  x × $ 2.25 + 9 -  x × $ 1.50 = $ 12

or,  x × $ 0.75 = 12 - 9

or, x =  = 4

The number of chips bag he can buy = x = 4

And The number of candy bar he can buy = 6 - x = 6 - 4 = 2

Hence Stephon can buy total 4 chips bag and 2 candy bar .  

7 0
3 years ago
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