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Mamont248 [21]
3 years ago
8

PLEASE HELP! WILL MARK BRAINLIEST!

Mathematics
1 answer:
AfilCa [17]3 years ago
5 0
Number 3 is the correct answer 
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Find the solution in slope-intercept form y+7=-3(x-1) and 3x+y=-4
Svetach [21]

Answer:

The slope intercept form of both given equations is : y =  - 3 x - 4.

Step-by-step explanation:

Here, the given equations are:

y +7 = -3 ( x - 1 )

and 3 x + y = - 4

Now,the SLOPE INTERCEPT FORM of any given equation is given as:

y = m x + C : here, C = Y - intercept, m = Slope

Consider equation (1):

y +7 = -3 ( x - 1 )    ⇒ y + 8 = - 3 x  + 3

or, y = -3x + 3 - 7 = -3x - 4

 ⇒ y =  -3x  -4

Hence, the slope-intercept form of the given equation is y =  -3x  -4.

Consider equation (2):

3 x + y = - 4    ⇒ y  = -4  - 3 x

 ⇒ y =  -3 x  - 4

Hence, the slope-intercept form of the given equation is y =  -3x  -4.

6 0
2 years ago
HElp fasttttttttttttttttttttttttt
Eduardwww [97]

9514 1404 393

Answer:

  -0.16

Step-by-step explanation:

The 'a' value can be found by looking at the difference between the y-value of a point 1 unit from the vertex, and the y-value of the vertex.

Here, that is a negative fraction of a unit. If we assume the value is a rational number that can be accurately determined from this graph, then we can find it by looking for a point where the graph crosses a grid intersection. It looks like such grid points are (-7, 0) and (3, 0). The vertex is apparently (-2, 4), so the vertex form of the equation is ...

  y = a(x +2)^2 +4

Using the point (3, 0), we have ...

  0 = a(3 +2)^2 +4 . . . . . fill in the values of x and y

  -4 = 25a . . . . . . . . . . subtract 4; next, divide by 25

  a = -4/25 = -0.16

7 0
2 years ago
Answering these questions
Rudiy27
1.\\ a)\ y=2x-3\ \ \ |subtract\ y\ from\ both\ sides\\\\\boxed{2x-y-3=0}\\\\b)\ y=\dfrac{1}{3}x-\dfrac{2}{5}\ \ \ |multiply\ both\ sides\ by\ 15\\\\15y=5x-3\cdot2\ \ \ |subtract\ 15y\ from\ both\ sides\\\\\boxed{5x-15y-6=0}


2.\\a)\ 5x-y+3=0\ \ \ |add\ y\ to\ both\ sides\\\\\boxed{y=5x+3}\\\\d)\ 7x+2y-3=0\ \ \ |subtract\ 7x\ from\ both\ sides\\\\2y-3=-7x\ \ \ |add\ 3\ to\ both\ sides\\\\2y=-7x+3\ \ \ \ |divide\ both\ sides\ by\ 2\\\\\boxed{y=-3.5x+1.5}


3.\\y=25x+100\ \ \ \ |subtract\ y\ from\ both\ sides\\\\\boxed{25x-y+100=0}
6 0
3 years ago
Yolanda is buying supplies for school. She buys n packages of pencils at $1.10 per package and m pads of paper at $2.30 each. Wh
Nikitich [7]
The first answer is C
The second answer is C
The third answer is B

Hope this helps!
8 0
3 years ago
In Which Quadrant is this true
34kurt

Given:

\sin \theta

\tan \theta

To find:

The quadrant in which \theta lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only \sin\theta and \csc\theta are positive.

In Quadrant III, only \tan\theta and \cot\theta are positive.

In Quadrant IV, only \cos\theta and \sec\theta are positive.

We have,

\sin \theta

\tan \theta

Here, \sin\theta is negative and \tan\theta is also negative. It is possible, if \theta lies in the Quadrant IV.

Therefore, the correct option is D.

5 0
3 years ago
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