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Dominik [7]
3 years ago
15

Point charges of 27 Q are placed at each corner of an equilateral triangle, which has sides of length 3 L. What is the magnitude

of the electric field at the mid-point of any of the three sides of the triangle in units of kQ/L2?

Physics
1 answer:
siniylev [52]3 years ago
5 0

Answer:

E_{net} = 2.25 KQ\L2

Explanation:

from figure

d = \sqrt { l^2 -(\frac{l}{2})^2}

  = \sqrt {\frac{3l^2}{4}

  = l\sqrt{ \frac{3}{4}}

net field at point P

E_{net} = E_1 -E_2 +E_3

= K\frac{q_1}{(\frac{l}{2})^2} -K\frac{q_2}{(\frac{l}{2})^2} +K\frac{q_3}{d^2}[tex][tex]q_1 =q_2 =q_3 =27Q

d = l\sqrt{ \frac{3}{4}}

E_{net}  = K\frac{27Q}{(\frac{l}{2})^2} -K\frac{27Q}{(\frac{l}{2})^2} +K\frac{27Q}{(l\sqrt{ \frac{3}{4}})^2}

E = \frac{27 KQ}{\frac{3}{4}l^2}                         {l =4l}

E_{net} = \frac{4 *36 KQ}{3{4l}^2}

E_{net} = 2.25 KQ\L2

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