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3 years ago

9

A force has both and _. Question 1 options: Speed and impact Magnitude and direction Motion and speed Direction and

motion.

1 answer:

Travka [436]3 years ago

5 0

Answer:

magnitude

and direction

Explanation:

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A(n) 6.6 kg bowling ball is rolling towards the bowling pins. If its momentum is 15.9 kg*m/s, how fast is it traveling, in m/s?

Vedmedyk [2.9K]

Answer:

2.4m/s towards the bowling pins

Explanation:

Given parameters:

Mass of the ball = 6.6kg

Momentum of the ball = 15.9kgm/s

Unknown:

Speed of the ball = ?

Solution:

The momentum is the amount of motion a body posses;

Momentum = mas x velocity

Insert the parameters and solve;

15.9 = 6.6 x velocity

velocity = 2.4m/s towards the bowling pins

3 0

3 years ago

A 59 kg man has a total mechanical energy of 150,023. J. If he is swinging downward and is currently 2.6 m above the ground, wha

Alborosie

Answer:

$v = 70.95 \ m/s.$

Explanation:

Given data:

Mass of the man, $m = 59 \ kg$

Total mechanical energy, $E_{i} = 150,023 \ \rm J$

Height, $h = 2.6 \ m$

Suppose there is no external force acting on the man. In this situation, the total mechanical energy (kinetic + potential) will remain steady.

Let the speed of the man at 2.6 m be <em>v</em>.

Thus,

$E_{i} = E_{f}$

$E_{i} = \frac{1}{2}mv^{2} + mgh$

$150023 = 0.5 \times 59 \times v^{2} + 59 \times 9.80 \times 2.6$

$\Rightarrow \ v = 70.95 \ m/s.$

6 0

3 years ago

Iron + Hydrochloric acid --> ?

marusya05 [52]

<h3>Iron - Fe</h3>

<h3>Hydrochloric Acid- HCl</h3>

<h2><u>Solution</u></h2>

$\bold{Fe +2HCl \rightarrow FeCl _{}{ \tiny2} + H{ \tiny{2}}}$

$\therefore \bold{\fbox{{Balanced}}}$

Iron + Hydrochloric Acid $\rightarrow$ Ferrous Chloride + Hydrogen

<h2>Hope This Helps You ❤️</h2>

8 0

3 years ago

Read 2 more answers

consider two stars, star a and star b. star a has a temperature of 4900 k , and star b has a temperature of 9900 k . how many ti

ValentinkaMS [17]

The Energy flux from Star B is 16 times of the energy flux from Star A.

We have Two stars - A and B with 4900 k and 9900 k surface temperatures.

We have to determine how many times larger is the energy flux from Star B compared to the energy flux from Star A.

<h3>State Stephen's Law?</h3>

Stephens law states that if E is the energy radiated away from the star in the form of electromagnetic radiation, T is the surface temperature of the star, and σ is a constant known as the Stephan-Boltzmann constant then-

$$\frac{Energy}{Area} = \sigma\times T^{4}$

Now -

Energy emitted per unit surface area of Star is called Energy flux. Let us denote it by E. Then -

$$E= \sigma\times T^{4}$

Now -

For Star A →

$T_{A}$ = 4900 K

For Star B →

$T_{B}$ = 9900 K

Therefore -

$$\frac{T_{B} }{T_{A} } =\frac{9900}{4900}$

$\frac{T_{B} }{T_{A} }=$ 2.02 = 2 (Approx.)

Now -

Assume that the energy flux of Star A is E(A) and that of Star B is E(B). Then -

$$\frac{E(B)}{E(A)} = \frac{\sigma\times T(B)^{4} }{\sigma \times T(A)^{2} }$

E(B) = E(A) x $(\frac{T(B)}{T(A)} )^{4}$

E(B) = E(A) x $2^{4}$

E(B) = 16 E(A)

Hence, the Energy flux from Star B is 16 times of the energy flux from Star A.

To learn more about Stars, visit the link below-

brainly.com/question/13451162

#SPJ4

4 0

2 years ago

A car moving along a straight level road has an initial speed of 3 m s-1 and its acceleration is 2 m s-2? What

BlackZzzverrR [31]

Answer:

13 ms-1

Explanation:

7 0

4 years ago

Read 2 more answers