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rjkz [21]
3 years ago
12

PLEASE HELP ME

Physics
2 answers:
vichka [17]3 years ago
8 0
Go with the last one because you need potential energy for kinetic energy
mrs_skeptik [129]3 years ago
4 0
It would be the last not the first . hope it helps
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A mechanic uses a mechanical lift to raise a car. The car weighs 11,000 N. The lift raises the car 2.5 m.
KengaRu [80]

Potential energy = (weight) x (height)

After the car has been raised 2.5 meters, it has

                 (11,000) x (2.5) = 27,500 Joules

MORE potential energy than it had before it was lifted.

That's the energy that has to come from the work you do to lift it.

Since no mechanical process is ever 100% efficient, the work required
to accomplish this task is <em>at least  27,500 joules</em>.


5 0
3 years ago
Read 2 more answers
What are the cahnges that a force can bring out on a body ? <br><br><br>Give examples
djyliett [7]
Hi Pupil Here is your answer ::




➡➡➡➡➡➡➡➡➡➡➡➡➡



1 The shape of the Body

Example : The shape of the ball lying on a floor can be changed by pressing it.


2 Direction of the Body

Example : The direction of motion of moving ball can be changed by hitting it with a bat.


3 The speed of the Body

Example : A ball at rest can be set in motion if force is applied only


4. Size of the Body

Example : The length of a spring tied and on one end can be increased by pulling it.




⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅




Hope this helps .......
5 0
3 years ago
Read 2 more answers
A 70.0-kg person throws a 0.0480-kg snowball forward with a ground speed of 33.5 m/s. A second person, with a mass of 55.0 kg, c
saw5 [17]

Answer:

The final velocity of the thrower is \bf{3.88~m/s} and the final velocity of the catcher is \bf{0.029~m/s}.

Explanation:

Given:

The mass of the thrower, m_{t} = 70~Kg.

The mass of the catcher, m_{c} = 55~Kg.

The mass of the ball, m_{b} = 0.0480~Kg.

Initial velocity of the thrower, v_{it} = 3.90~m/s

Final velocity of the ball, v_{fb} = 33.5~m/s

Initial velocity of the catcher, v_{ic} = 0~m/s

Consider that the final velocity of the thrower is v_{ft}. From the conservation of momentum,

&& m_{t}v_{ft} + m_{b}v_{fb} = (m_{t} + m_{b})v_{it}\\&or,& v_{ft} = \dfrac{(m_{t} + m_{b})v_{it} - m_{b}v_{fb}}{m_{t}}\\&or,& v_{ft} = \dfrac{(70 + 0.0480)(3.90) - (0.0480)(33.5)}{70}\\&or,& v_{ft} = 3.88~m/s

Consider that the final velocity of the catcher is v_{fc}. From the conservation of momentum,

&& (m_{c} + m_{b})v_{fc} = m_{b}v_{it}\\&or,& v_{fc} = \dfrac{m_{b}v_{it}}{(m_{c} + m_{b})}\\&or,& v_{fc} = \dfrac{(0.048)(33.5)}{(55.0 + 0.0480)}\\&or,& v_{fc} = 0.029~m/s

Thus, the final velocity of thrower is 3.88~m/s and that for the catcher is 0.029~m/s.

8 0
3 years ago
The temperature inside my refrigerator is about 4 degrees C. If I place a balloon in my fridge that initially has a temperature
maksim [4K]

v

Convert the given temperatures from celsius to kelvin since we are dealing with gas.

To convert to kelvin, add 273.15 to the temperature in celsius.

T1 = 22 + 273.15 = 295.15 k

T2 = 4 + 273.15 = 277.15 k

V1 = 0.5 L

Let's find the final volume (V2).

To solve for V2 apply Charles Law formula below:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

5 0
1 year ago
How much time does it take for a car to accelerate from 3.44 m/s to 20.9 m/s if the average acceleration is 6.00 m/s^3
miv72 [106K]

Do you go to GA Connexus Academy??

4 0
4 years ago
Read 2 more answers
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