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3 years ago

Martin uses his power saw every 15 seconds.How many times did he use it in one hour ?

Mathematics

2 answers:

Travka [436]3 years ago

8 0

Answer:

60/15=4

Step-by-step explanation:

He uses his power saw every 15 that inside of an hour is 4 because when you do the division its going to = 4

Alina [70]3 years ago

7 0

Answer:

60÷15 =4

Therefore Martin uses his power saw 4 times in one hour 

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Check the picture below.

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$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24$

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3 years ago

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Step-by-step explanation:

all you have to do is replace in the following formula

$\sqrt{(x2-x1)^{2}+ (y2-y1)^{2}} =d$

Where

X1: is the first number of the first point

Y1: is the second number of the first point

X2: is the first number of the second point

Y2: is the second number of the second point

you replace in the formula and solve

I attach solution

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2 years ago

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3 years ago

Martin uses his power saw every 15 seconds.How many times did he use it in one hour ?​

Martin uses his power saw every 15 seconds.How many times did he use it in one hour ?