If
is the first number in the progression, and
is the common ratio between consecutive terms, then the first four terms in the progression are

We want to have

In the second equation, we have

and in the first, we have

Substituting this into the second equation, we find

So now we have

Then the four numbers are

Answer:
Increased by a factor of 4
Step-by-step explanation:
The original circumference is:
C1 = 2 * pi * r1
The new circumference is:
C2 = (2 * pi * r2)
"circumference that is 4 times larger than the original"
(2 * pi * r2) = 4 (2 * pi * r1)
Rewriting:
r2 = 4r1
Answer:
The radius of the original circle is:
increased by a factor of 4
Hope this helps :)
Answer:
2q+6
Step-by-step explanation:
So basically, you would do this.
-2q-6+6q+12-2q
Next
-4q+6q = 2q
12-6=6
2q+6
Answer:
A.6.2i-4.2 j
Step-by-step explanation:
We are given that



We have to find the projection of w on to u.
The project of vector a on b
=


Using the formula
The projection of w on to u

The projection of w on to u=6.2i-4.2j
Hence, option A is true.
Answer:
d = Sqrt 41 = 6.4
Step-by-step explanation:
d = sqrt [(x-x)^2 + (y-y)^2]
d = sqrt [(-7 - - 2)^2 + (7-3)^2]
d = sqrt[(-7+2)^2 + (4)^2]
d = sqrt [(-5)^2 + (4)^2]
d= sqrt (25 + 16)
d = sqrt 41 = 6.4