You cannot solve for x but you can factor
to solve in ax^2+bx+c form you must find
b=x+y
a times c=x times y
so solve
3 times 3=9
what 2 number multily to get 9 and add to get 10
9=x times y
the numbers are 9 and 1 so
3x^2+1x+9x+3
(3x^2+1x)+(9x+3)
factor
(x)(3x+1)+(3)(3x+1)
reverse distribute
ab+ac=a(b+c)
(x)(3x+1)+(3)(3x+1)=(x+3)(3x+1)
factored out form is (x+3)(3x+1)
There are 3. They're 16,25 and 36
The sum of the first n natural numbers and 0=
n*(n+1)/2
Hey. Let me help you on this one.
Let's break this problem down so it's easier for us to comprehend it.
There are 850 students in the school, and the amount of female students equals to the amount of male students + sixty additional females.
Amount of students in school = 850 students
Male students =

Female students =

Let's form an equation so we can work with what we have.

Subtract 60 from both sides.

Simplify

Divide both sides by 2.

Answer: There are 395 male students, and 455 female students.
Answer:
x=4
Step-by-step explanation:
First you want to add 8.8 to 7.2 and get 16 because you want to get x alone
Next divide divide 4x on both sides so 4x/4x cross out and left with just x. 16/4 =4
x=4
Hope this helps!