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Semmy [17]
4 years ago
6

Determine the projection of w onto u.

Mathematics
2 answers:
Aliun [14]4 years ago
5 0

Answer:

a

Step-by-step explanation:

irina [24]4 years ago
4 0

Answer:

A.6.2i-4.2 j

Step-by-step explanation:

We are given that

u=9i-6j

v=-3i-2j

w=19i+15j

We have to find the projection of w on to u.

The project of vector a on b

=\frac{a\cdot b}{\mid b\mid^2}b

w.u=(19i+15j)\cdot (9i-6j)=171-90=81

\mid u\mid=\sqrt{x^2+y^2}=\sqrt{9^2+(-6)^2}=\sqrt{117}

Using the formula

The projection of w on to u

=\frac{u\cdot w}{\mid u\mid^2}(u)=\frac{81}{117}(9i-6j)

The projection of w on to u=6.2i-4.2j

Hence, option A is true.

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There is an 8% increase

Step-by-step explanation:

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Now finish solving to get

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Shalnov [3]
Hi there!

Given:
4m +  \frac{23 + n}{p - 3}  \\ m = 7 \\ n = 2 \\ p = 8

In order to evaluate the expression with the given values of m, n and p, we must substitute then into the expression. Then we use the correct order of operations (PEMDAS) to calculate.

Let's substitute first!
4(7)  +  \frac{(23 + 2)}{(8 - 3)}

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28 +  \frac{25}{5}

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7 0
3 years ago
A triangular plate with base 2 m and height 3 m is submerged vertically in water so that the tip is even with the surface. Expre
g100num [7]

Answer:

Hydrostatic Force = 35.28KN

Step-by-step explanation:

To solve this question, let's consider integrating the hydrostatic force from the top of the triangle to the bottom.

Formula for a thin horizontal slice of the triangle the force is;

δF=ρgxwδx

Where w is width of triangle; ρ is density of water and g is acceleration due to gravity

At depth x, the width of the triangle is w=2/3x.

Thus, F = (3,0)∫)ρgxwδx

=(2/3)ρg[(3,0)∫)x²δx]

= integrating, we have;

F = (2/3)ρg[(3³/3) - (0³/3)]

F = (2/5)ρg [27/3] = (2/5)(1000)(9.8)(9) = 35280 N = 35.28 KN

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4 years ago
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