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prisoha [69]
3 years ago
11

Find the length of the second base of a trapezoid with one base measuring 18 feet, a height of 5.3 feet, and an area of 125.4 sq

uare feet.​
Mathematics
1 answer:
faltersainse [42]3 years ago
6 0

Answer:

29.32 feet

Step-by-step explanation:

area of a trapezoid = height/2 * (first base + second base)

125.4 = 5.3 / 2 * (18 + second base)

125.4 = 2.65 * (18 + second base)

We want to solve for the second base. To do this, we can start by isolating the (18+second base) by dividing each side by 2.65

47.32 = 18 + second base

subtract 18 from both sides to solve for the second base

29.32 = second base

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MATH QUESTION!! WILL MARK BRAINLIEST!! PAST DUE HELP ASAP!!!
monitta

Answer:

<em>Proof below</em>

Step-by-step explanation:

<u>Right Triangles</u>

In any right triangle, i.e., where one of its internal angles is 90°, some interesting relations stand. One of the most-used is Pythagora's Theorem.

In a right triangle with shorter sides a and b, and longest side c, called the hypotenuse, the following equation is satisfied:

c^2=a^2+b^2

The image provided in the question shows a line passing through points A(0,4) and B(3,0) that forms a right triangle with both axes.

The origin is marked as C(0,0) and the point M is the midpoint of the segment AB. We have to prove.

CM=\frac{1}{2}AB

First, find the coordinates of the midpoint M(xm,ym):

\displaystyle x_m=\frac{0+3}{2}=1.5

\displaystyle y_m=\frac{4+0}{2}=2

Thus, the midpoint is M( 1.5 , 2 )

Calculate the distance CM:

CM=\sqrt{(1.5-0)^2+(2-0)^2}

CM=\sqrt{2.25+4}=\sqrt{6.25}=2.5

CM=2.5

Now find the distance AB:

AB=\sqrt{(3-0)^2+(4-0)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}

AB=5

AB/2=2.5

It's proven CM is half of AB

3 0
3 years ago
Write an equation of a line through (4,-1), parallel to y = 1x – 5<br><br>​
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Step-by-step explanation:

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