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3 years ago

Find the value of X.

Mathematics

1 answer:

miv72 [106K]3 years ago

4 0

Answer:

x = 8√2 units

Step-by-step explanation:

On a 45-45-90 triangle, the ratio between one of the legs (both are congruent) and the hypotenuse is 1 : √2 (Improper but it still sends the message). That means the hypotenuse is √2 times as long as a leg.

x = 8 × √2

x = 8√2 units

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3 years ago

Evaluate. <img src="https://tex.z-dn.net/?f=%20-%20%20%5Csqrt%7B81%7D%20" id="TexFormula1" title=" - \sqrt{81} " alt=" - \s

loris [4]

Answer:

Step-by-step explanation:

First find factors of 81

3 81

3 27

3 9

3 3

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5 0

2 years ago

The Great Pyramid in Giza, Egypt, is a square pyramid. The dimensions of the pyramid at the time of its completion are shown in

ryzh [129]

Answer:

Area of square pyramid is $153883.8\ m^{2}$ .

Step-by-step explanation:

Diagram of the given scenario is shown below,

Given that,

The Great Pyramid in Giza, Egypt is a square pyramid. The area of base shape is made up with square is $154 \ m^{2}$ . The side of the square is $230 \ m$ and The height of each triangle is $187 \ m$ .

So, Area of Square shape = $154 \ m^{2}$

Side of square = $230 \ m$

Height of each triangle = $187 \ m$

Finding the Height of triangular shape which is here known as slant height.

In Δ ABO, applying Right angle pythagorean Theorem,

Base $(BO)$ = $\frac{230}{2} = 115\ m$

Height $(AO)$ = $187\ m$

Now,

∴ $AB^{2} = AO^{2} \ + \ BO^{2}$

⇒ $AB= \sqrt{AO^{2} \ + \ BO^{2} }$

⇒ $AB= \sqrt{187^{2} \ + \ 115^{2} }$

⇒ $AB= \sqrt{34969 \ + \ 13225 }$

⇒ $AB= 219.53 \ m$

Then,

Area of square pyramid = $area \ of \ square + \ 4\times area \ of \ traiangle$

= $side\times side + 4\times\frac{1}{2}\times AB\times Base$

= $230\times 230 \ + 2\times 219.53\times 230$

= $52900 + 100983.8$

= $153883.8 \ m^{2}$

Hence, Area of square pyramid is $153883.8\ m^{2}$ .

6 0

2 years ago

Find the value of y in the equation

iren2701 [21]

We want to find y from the equation
$\frac{3}{y-2} =8$

Multiply each side by (y - 2).
$(y-2).( \frac{3}{y-2)}) = 8(y-2)$
Note that (y-2) in the numerator and denominator cancel out on the left side.
Therefore
3 = 8(y - 2)
3 = 8y - 16
Add 16 to each side.
3 + 16 = 8y - 16 + 16
19 = 8y
Divideach side by 8.
19/8 = y

Answer: $y= \frac{19}{8}$

4 0

3 years ago

Find the value of X.​

Find the value of X.