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3 years ago

When constructing a tangent line to a circle, what two objects are drawn first?

Mathematics

2 answers:

lara31 [8.8K]3 years ago

8 0

Hey there!

Your answer will be B) circle and a point

Hope it helps!

Mariulka [41]3 years ago

5 0

That's correct the answer is indeed B).

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Question 5

Maksim231197 [3]

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8 0

3 years ago

Write 6^7 + 6^5 + 11 in base six. Use the digits 0, 1, 2, 3, 4, 5

Zielflug [23.3K]

Answer:

Sorry I don't remember the answer

6 0

3 years ago

Five members of the computer club site to buy used computer dividing up the cost equally later three new members join a club of

BartSMP [9]

The computation shows that the price of the used computer is $75.

<h3>How to compute the price?</h3>

From the information given, it should be noted that there are 5 members before the new members joined and $15 was given to each member.

Therefore, the price of the used computer will be:

= $15 × 5

= $75

The price of the used computer is $75.

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

7 0

1 year ago

In a geometric sequence, the term a n+1 can be smaller than the term a n

Rainbow [258]

Do you mean a_(n+1), worded a sub (n+1)?

If so yes. If the function of the sequence is getting smaller or more negative with each term.

6 0

3 years ago

Calculating the degrees of freedom, the sample variance, and the estimated standard error for evaluations using the t statistic

Yuliya22 [10]

Answer:

a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

b) $s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

c) For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

Step-by-step explanation:

Part a

For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

Part b

From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

$SS = \sum_{i=1}^n (X_i -\bar X)^2$

And the sample variance for this case can be calculated from this formula:

$s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

Part c

For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

8 0

3 years ago