Question

What is the equation of the line that passes through the points (−2, 1) and (1, 10)?

Answer 1

Hello 
let : A(-2;1)   B(1:10) and the equation is: y = ax+b
a = (yb -ya)/(xb -xa)
a = (10-1)/(1+2)
a = 3........ y = 3x+b
A passes by this line : 1 = 3(-2)+b
 b = 7
the equation is : y= 3x+7

Answer 2

Answer:

Equation of the line will be y = 3x + 7

Step-by-step explanation:

We have to find the equation of a line that passes through two points having coordinates as (-2, 1) and (1, 10) respectively.

Equation of the line in intercept form is represented by y = mx + c

Where m = slope of the line

c = y-intercept

Now we know slope of the line is represented by m = $\frac{(y-y')}{(x-x')}$

m = $\frac{(10-1)}{(1+2)}$

m = $\frac{9}{3}$

m = 3

Now the equation of the line will be y = 3x + c

Since point (1, 10) lies on the given line

So 10 = 3×1 + c

c = 10 - 3

c = 7

Finally the equation of the line will be y = 3x + 7