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3 years ago

5

Show that (3√2-1)² + (3+√2)² is an integer and find its value

1 answer:

Lorico [155]3 years ago

8 0

Answer:

value: 30

Step-by-step explanation:

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Okay...last time i ask. 4ths times a charm i suppose. please help. will mark brainliest. ill even write you a frickisagfbsdfn po

barxatty [35]

Ok, so when it says "3x, x $\leq$ 2," it means that when the x value is less than or equal to 3, you graph 3x. You would have the following points on the line: (-3,-9), (-2,-6), (-1,-3), (0,0), (1,3), and (2,6). The endpoint of the ray on the left side (the points I just said) would be (2,6)

When it says, "1/2 x +5, 2 $\leq$ x," it means that when the value of x is greater than or equal to 2, the y value is .5x + 5. You would graph the following points: (2,6), (4,7), (6,8), and (8,9). The endpoint of th ray on the right (the points I just said) would be (2,6).

Keep in mind that though the graph is continuous, it isn't one line, but 2 rays (which you probably already know).

6 0

3 years ago

Jackson’s puppy eats 24 ounces of feed every day an object with a weight of 1 ounce has a mass that is approximately equal to 28

kati45 [8]

Answer:

8

Step-by-step explanation:

bc hdibdjs

4 0

3 years ago

A coin is flipped eight times where each flip comes up either heads or tails. How many possible outcomes a) are there in total?

attashe74 [19]

Answer:

There are 256 ways in total.

There are 56 possible outcomes contain exactly three heads.

The possible outcomes contain at least three heads is 219.

The possible outcomes contain the same number of heads and tails are 70.

Step-by-step explanation:

Consider the provided information.

A coin is flipped eight times where each flip comes up either heads or tails.

Part (a) How many possible outcomes are there in total?

Each time we flip a coin it comes up either heads or tail.

Therefore the total number of ways are:

$2\times 2\times 2\times 2\times 2\times 2\times 2\times 2=2^8=256$

Hence, there are 256 ways in total.

Part (b) contain exactly three heads?

We want exactly 3 heads, therefore,

n=8 and r=3

According to the definition of combination: $\binom{n}{r}=\frac{n!}{r!(n-r)!}$

$\binom{8}{3}=\frac{8!}{3!(5)!}=56$

Hence, there are 56 possible outcomes contain exactly three heads.

Part (c) contain at least three heads?

For 3 heads: $\binom{8}{3}=\frac{8!}{3!(5)!}=56$

For 4 heads: $\binom{8}{4}=\frac{8!}{4!(4)!}=70$

For 5 heads: $\binom{8}{5}=\frac{8!}{5!(3)!}=56$

For 6 heads: $\binom{8}{6}=\frac{8!}{6!(2)!}=28$

For 7 heads: $\binom{8}{7}=\frac{8!}{7!(1)!}=8$

For 8 heads: $\binom{8}{8}=1$

Now add them as shown:

56+70+56+28+8+1=219

Hence, the possible outcomes contain at least three heads is 219.

Part (d) contain the same number of heads and tails?

Same number of heads and tails means that the value of r=4.

Therefore,

$\binom{8}{4}=\frac{8!}{4!(4)!}=70$

Hence, the possible outcomes contain the same number of heads and tails are 70.

6 0

3 years ago

write two additional sentences where the sum is negative. in each sentence one added should be positive and the other

Goshia [24]

10 + (-5) = 10 - 5 = 5

-11 + 20 = 20 + (-11) = 20 - 11 = 9

102 + (-1) = 102 - 1 = 101

<span>-20 + 60 = 60 + (-20) = 60 - 20 = 40 </span>

6 0

3 years ago

Find value of k

insens350 [35]

Answer:

k=10BY DPING PROCESS IT BECOME

3 0

3 years ago