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NNADVOKAT [17]
3 years ago
14

14. The sum of two integers is – 1.d

Mathematics
1 answer:
Alexxandr [17]3 years ago
3 0

Answer:

a)The integers could be : -3 and 2

                                      -4 and 3

                                      -5 and 4

                                      -9 and 10

                                      --------------

   b) the integers could be any pair -(x+1) and x  with x a natural number

Step-by-step explanation:

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If the shape of an object changes the perimeter will always change true or false
Ugo [173]

The answer is false due to the object is changes shape not size

6 0
3 years ago
A small company 's net income for the first 6 months of the year was 76.500 and for the last six months it was 100,000 . What is
inna [77]

Answer:The ratio of net income in the first 6 months, to the last six months is $76,500 / $100,000. This simplifies intuitively as follows:

76500/100000

Dividing by 100: 765/1000

Dividing by 5: 153/200

The denominator 200 is only divisible by the prime numbers 2 and 5, and since the numerator 153 is not divisible by either 2 or 5, this means that this is in simplest form, and the final answer is 153/200.

Step-by-step explanation:i did the research for you this isnt my own answer therefore don't give me the credit. but hope this helped you tho :D

5 0
3 years ago
a rectangle prism has a volume of 3x^2 + 18x+ 24. its base has a length of x + 2 and width of 3, what expression represents the
OlgaM077 [116]
\bf \textit{volume of a rectangular prism}\\\\
V=lwh\qquad 
\begin{cases}
l=x+2\\
w=3\\
V=3x^2 + 18x+ 24
\end{cases}\implies \cfrac{V}{lw}=h
\\\\\\
\cfrac{3x^2 + 18x+ 24}{3(x+2)}=h\implies \cfrac{\underline{3}(x^2 + 6x+ 8)}{\underline{3}(x+2)}=h
\\\\\\
\cfrac{(x+4)\underline{(x+2)}}{\underline{(x+2)}}=h\implies x+4=h
6 0
3 years ago
Fins the zeroes of the quadratic equation : 4√ 5 x^ 2 - 24x - 9√ 5
liubo4ka [24]

Answer:

Step-by-step explanation:

Hello,

First of all, we know that the solution of the following equation

   ax^2+bx+c=0

are

   \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} \ \text{ when } \Delta=b^2-4ac \geq 0

<em>I would suggest that you try to apply this formula first and check the solution only after you try.</em>

Let's apply it in this case, we have:

a=4\sqrt{5} \\ \\ b=-24 \\ \\ c= -9\sqrt{5}

\Delta=b^2-4ac=24^2+4*9*5=1296 \\ \\ \sqrt{\Delta}=36 \ \text{ and the solutions are } \\ \\ \\ x_1=\dfrac{24-36}{8\sqrt{5}}=\dfrac{-12}{8\sqrt{5}}=\boxed{\dfrac{-3}{2\sqrt{5}}} \\ \\x_2=\dfrac{24+36}{8\sqrt{5}}=\dfrac{60}{8\sqrt{5}}=\boxed{\dfrac{15}{2\sqrt{5}}}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0
3 years ago
Can someone solve this? Please!!!!<br> You just need to solve for X in the drawing
Nadya [2.5K]

Answer:

3y and 1y

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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