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ser-zykov [4K]
3 years ago
12

Three elements are represented by the letters A, B, and C. the three elements have the same number of valence electrons. Element

C has electrons in three energy levels and element A is the lightest of the three. Elements B has a total of twenty electrons. Identify the elements.
Chemistry
1 answer:
AfilCa [17]3 years ago
3 0
Answer:
A- beryllium
B- calcium
C- magnesium

Explanation
NOTE: all element in group 2 have 2 balance electrons

First let’s start with B- number of electrons= number of protons which is equal to the atomic number. therefore, the answer is calcium as it’s atomic number is 20

C- magnesium will have three energy levels considering it has 12 electrons (2,8,2).

A- beryllium is the lightest one in group 2 as it has the atomic mass of 9.0122.
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We are given:

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\frac{1.88atm\times 285mL}{355K}=\frac{2.50atm\times 435mL}{T_2}\\\\T_2=\frac{2.50\times 435\times 355}{1.88\times 285}=720.5K

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