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Zina [86]
3 years ago
10

What amount (moles) is represented by each of these samples?

Chemistry
1 answer:
Zinaida [17]3 years ago
5 0
<h3>Answer:</h3>

                  a)  Moles of Caffeine  =  1.0 × 10⁻⁴ mol

                  b) Moles of Ethanol   =  4.5 × 10⁻³ mol

<h3>Solution:</h3>

Data Given:

                  Mass of Caffeine  =  20 mg  =  0.02 g

                  M.Mass of Caffeine  =  194.19 g.mol⁻¹

                  Molecules of Ethanol  =  2.72 × 10²¹

Calculate Moles of Caffeine as,

                               Moles  =  Mass ÷ M.Mass

Putting values,

                               Moles  =  0.02 g ÷ 194.19 g.mol⁻¹

                                Moles  =  1.0 × 10⁻⁴ mol

Calculate Moles of Ethanol as,

                                                         As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Particles and Avogadro's Number is given as,

                          Number of Moles  =  Number of Molecules ÷ 6.022 × 10²³

Putting values,

                          Number of Moles  =  2.72 × 10²¹ Molecules ÷ 6.022 × 10²³

                          Number of Moles  =  4.5 × 10⁻³ Moles

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Chromosomes have hereditary function that are capable of self-duplication and they have thread-like structures seen inside the nucleus of plant and animal. In plants, they go through a cycle called alteration of generation that has multicellular stages. One is sporophyte that is a diploid, and the other is gametophyte with a haploid.

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You need a 30% alcohol solution. On hand, you have a 200 mL of a 10% alcohol mixture. You also have 55% alcohol mixture. How muc
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Answer: 160 ml

Explanation:

The expression used will be :

C_1V_1+C_2V_2=C_3V_3

where,

C_1 = concentration of Ist alcohol solution= 10%

C_2 = concentration of 2nd alcohol solution= 55%

V_1 = volume of Ist alcohol solution = 200 ml

V_2 = volume of  2nd alcohol solution= v ml

C_3 = concentration of resulting alcohol solution= 30%

V_2 = volume of resulting alcohol solution= (v+200) ml

Now put all the given values in the above law, we get the volume of added.

(10\times 200)+(55\times v)=(30\times (v+200)ml)

By solving the terms, we get :

v=160ml

Therefore, the volume of 55% mixture  needed to be added to obtain the desired solution is 160 ml.

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