If 6.4 miles of Fe react with excess O2, how many miles of Fe2O3 can be formed? 4 Fe + 3 O2 -> 2 Fe2O3
1 answer:
I'm assuming that by "miles" you mean moles.
If O2 is the excess reactant, that means Fe is the limiting reactant. That means that the amount of product being formed depends on the amount of Fe reactant present. To calculate the moles of Fe2O3 formed, start with the given 6.4 moles of Fe and use the mole to mole ratio given by the reaction as shown below:
6.4 mol Fe x
= 3.2 mol Fe2O3
If O2 is the excess reactant, that means Fe is the limiting reactant. That means that the amount of product being formed depends on the amount of Fe reactant present. To calculate the moles of Fe2O3 formed, start with the given 6.4 moles of Fe and use the mole to mole ratio given by the reaction as shown below:
6.4 mol Fe x
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I'm not sure how many sign fig's you are required to have.
However I think the final answer would be 0.05 Moles, because of the .5g, that is considered 1 sign fig.
However I think the final answer would be 0.05 Moles, because of the .5g, that is considered 1 sign fig.
Answer:
+1
Explanation:
For the equation to be balanced, the total mass number and the total atomic number on both side of the equation but be equal.
This is illustrated:
For the mass number:
Left side: 22
Right side: 22 + 0 = 22
For the atomic number:
Left side: 11
Right side: 10 + x
11 = 10 + x
Collect like terms
x = 11 - 10
x = 1
See attachment for further explanation.
