Answer:
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>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2
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In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28
0
and ∠QRT=65
0
, then find the values of x and y.
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Solution
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Given, PQ⊥PS,PQ∥SR,∠SQR=28
∘
,∠QRT=65
∘
According to the question,
x+∠SQR=∠QRT (Alternate angles as QR is transversal.)
⇒x+28
∘
=65
∘
⇒x=37
∘
Also ∠QSR=x
⇒∠QSR=37
∘
Also ∠QRS+∠QRT=180
∘
(Linear pair)
⇒∠QRS+65
∘
=180
∘
⇒∠QRS=115
∘
Now, ∠P+∠Q+∠R+∠S=360
∘
(Sum of the angles in a quadrilateral.)
⇒90
∘
+65
∘
+115
∘
+∠S=360
∘
⇒270
∘
+y+∠QSR=360
∘
⇒270
∘
+y+37
∘
=360
∘
⇒307
∘
+y=360
∘
⇒y=53
∘
Step-by-step explanation:
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Answer:
i think it would be 10,000
I hope it helped!
In this case, we'll have to carry out several steps to find the solution.
Step 01:
data:
7x
Step 02:
We must analyze the equation to find the solution.
x = 29:
7 (29) = 203
The answer is:
203
Answer: yes it is a right angle triangle
Step-by-step explanation:
a^2 + b^2 = c^2
8^2+ 5^2 = ?
64 + 25 = square root of 89
square root of 89 = 9.4
when we round 9.4 it is 9
so
22- (8+5) =
22 - 13 = 9
so our answer is correct
Answer:
8 and 3
Step-by-step explanation:
11+11=22
That means that the perimeter is 22.
8+3+8+3= 22 so the answer is 8 and 3!
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