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Verdich [7]
3 years ago
7

A save percentage in lacrosse is found by dividing the number of saves by the number of shots faced. A lacrosse goalie saved 6 o

f 13 shots. How many additional consecutive saves s must the goalie make to raise his save percentage to 0.850?
Mathematics
1 answer:
Crazy boy [7]3 years ago
4 0

Answer:

Additional saves = <u>34 lacrosse.</u>

Step-by-step explanation:

 The additional saves = s

Then , the number of saves becomes  = 6+s

and, the number of shots faced = 13+s

Save percentage in lacrosse is found by dividing the number of saves by the number of shots faced that is

\text{ percentage\ in\ lacrosse} =\frac{\text the \ number\ of \ saves}{\text the \ number of shots faced }

\text{ percentage\ in\ lacrosse} =\frac{6+s}{13+s }

Given , the percentage of lacrosse = 0.850

{0.850 } =\frac{6+s}{13+s }

{0.850 \times}({13+s })=6+s

11.05+0.850s=6+s

11.05-6=s-0.850s

5.05=0.15s

s=33.66

Since, additional saves must be an integer so round it off to the nearest integer 34.

Thus, Additional saves = <u>34 lacrosse.</u>

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