Answer: John's situation
Step-by-step explanation:
Hi, to answer this question we have to write an equation for each situation.
John’s situation:
The amount of money that John has (y) is equal to his school account (40) minus the product of the number of days (x) and the amount he spends per day( 3)
y =40-3x
As days pass by, John has less money (negative rate of change)
Judy's situation
The amount of money that Judy has in her savings account (y) is equal to the product of the number of days (x) and the amount he saves per day (20/2)
y = x (20/2)
Add 73 + 15 + 8 then subtract it from 190 :) hope I helped
Complete question :
Point K on the number line shows Kelvin's score after the first round of a quiz: A number line is shown from negative 10 to 0 to positive 10. There are increments of 1 on either side of the number line. The even numbers are labeled on either side of the number line. Point K is shown on 3. In round 2, he lost 9 points. Which expression shows how many total points he has at the end of round 2? 3 + (−6) = −9, because −9 is 6 units to the left of 3 3 + 6 = −9, because −9 is 6 units to the left of 3 3 + (−9) = −6, because −6 is 9 units to the left of 3 3 + 9 = −6, because −6 is 9 units to the left of 3
Answer: 3 + (−9) = −6, because −6 is 9 units to the left of 3
Step-by-step explanation:
Given the following :
Width of number line = - 10 to + 10
Point K on the number line = +3 ( kelvin's score after the first round of quiz).
If Kelvin losses 9 points in round 2 = - 9
Hence at the end of round 2, He'll have a total of :
Point at the end of round 1 + point lost in round 2
3 + (-9) = - 6
Answer:
<h2><u><em>
a²+2ab+b²-c²</em></u></h2>
Step-by-step explanation:
Solve:
(a+b+c) (a+b-c)=
(a²+ab-ac+ab+b²-bc+ac+bc-c²)=
a²+ab-ac+ab+b²-bc+ac+bc-c²=
a²+2ab+0ac+b²+0bc-c²=
a²+2ab+b²-c²
Answer: f(x)-g(x)=2x+5
Step by step:
f(x) = 3x+2
g(x) = x-3
f(x)-g(x) = 3x +2 - (x-3) = 3x + 2-x+3=2x+5