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Mariulka [41]
3 years ago
7

Describe how a root can be written using a rational expression. Give an example.

Mathematics
2 answers:
Paladinen [302]3 years ago
8 0

Answer: To find the roots of a Rational Expression we only need to find the the roots of the top polynomial, so long as the Rational Expression is in "Lowest Terms". Lowest Terms means when the top and bottom of a fraction have no common factors.

     

Step-by-step explanation:

user100 [1]3 years ago
4 0

Answer:

√36 = 6

³√ 5 = 5 ^ ⅓

⁴√ 16 = 16 ^ ¼

= 2

Step-by-step explanation:

Mathematically, the square of a number, is the power of 2 to the base of that number, or the exponent 2 to the base of that number.

Such as :

The Square of 5.

=5²

= 5*5 = 25.

In thesame vain, the SQUARE of a number is to the power 2 of that number.

Hence, the SQUARE ROOT, of any number is the ROOT 2 , to that number. Such that:

Square roots of 5:

√5

= 5 ^½

√12

= 12 ^ ½

√36

= 36 ^ ½

= 6

For other expression other than 2, the rational expression will be a function of the value before the root.

Such that:

1. ³√5 = 5 ^ ⅓

2. ³√ 12 = 12 ^ ⅓

3. ³√8 = 8 ^ ⅓ = 2

4. ⁴√ 16 = 16 ^ ¼ = 2

5. ⁴√24 = 24 ^ ¼

The other goes on and on in that order

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Plz help me with this
Nitella [24]

Answer: C) y ≥ 3x - 2;  y\leq \dfrac{1}{2}x+3

<u>Step-by-step explanation:</u>

Blue line:

y-intercept (b) = -2

slope (m) is 3 up, 1 right = 3

shading is above

⇒ y ≥ 3x - 2

Yellow line:

y-intercept (b) = 3

slope (m) is 1 up, 2 right = \dfrac{1}{2}

shading is below

\implies \bold{y\leq \dfrac{1}{2}x+3}

8 0
4 years ago
Solve the triangle.<br><br> B = 36°, a = 41, c = 20
svetoff [14.1K]

Answer:

See below

Step-by-step explanation:

When you have 2 sides and the angle between them you use the cosine theorem or law of cosines:

b^{2}=a^{2}+c^{2}-2acCos(B)

b^{2}=41^{2}+20^{2}-2(41)(20)cos36 \\b^{2}=1681 + 400-1327 \\b^{2}=754 \\b = 27.5

After you have a side and the opposed angle (side b and angle B), you use the law of sines:

\frac{a}{sinA} =\frac{b}{sinB}=\frac{c}{sinC}

I will calculate angle A first:

[tex]\frac{27.5}{sin36} =\frac{41}{sinA} \\sinA =\frac{41}{27.5} sin36 \\sin A = 0.876 \\A = 61.2\°[/tex]

Same for angle C:

\frac{27.5}{sin36} =\frac{20}{sinC} \\sinC =\frac{20}{27.5} sin36 \\sin C = 0.427 \\C = 25.3\°

The sum of the angles is 36° + 61.2° + 25.3° = 122.5°; The sum must be 180° so this isnt a triangle.

I re did the problem using B as 63° instead of 36° in case you wrote it wrong and I got a satisfactory answer.

using B = 36:

b = 36.6

angle A = 86.4°

angle C = 29.1°

A+B+C = 86.4° + 29.1° + 63° = 178.5° ~ 180°

5 0
3 years ago
Plz helppppp asappppppp​
olchik [2.2K]
Ok so the rectangle is 12x6 which is 72. The entire top part is 18 which means the other triangle side is 6. 6x6 = 36 so 72+36 is 108
7 0
3 years ago
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5x + 2y = 7<br> 7x + 6y = -3<br> Please solve using elimination method.
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X=3 y=-4
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Jose sells beaded necklaces. Each large necklace sells for $4.70 and each small necklace sells for $3.80 How much will he earn f
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He will have $13.5
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